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Amy is pulling a wagon with a force of 30 pounds up a hill at an angle of 25°. Give the force exerted on the wagon as a vector a

Fofino [41]

Answer:

Vector (ordered pair - rectangular form)

$\vec F = (27.189,12.679)\,[lbf]$

Vector (ordered pair - polar form)

$\vec F = (30\,lbf, 25^{\circ})$

Sum of vectorial components (linear combination)

$\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]$

Step-by-step explanation:

From statement we know that force exerted on the wagon has a magnitude of 30 pounds-force and an angle of 25° above the horizontal, which corresponds to the +x semiaxis, whereas the vertical is represented by the +y semiaxis.

The force ( $\vec F$ ), in pounds-force, can be modelled in two forms:

Vector (ordered pair - rectangular form)

$\vec F = \left(\|\vec F\|\cdot \cos \theta, \|\vec F\|\cdot \sin \theta\right)$ (1)

Vector (ordered pair - polar form)

$\vec F = \left(\|\vec F\|, \theta\right)$

Sum of vectorial components (linear combination)

$\vec {F} = \left(\|\vec F\|\cdot \cos \theta\right)\cdot \hat{i} + \left(\|\vec F\|\cdot \sin \theta \right)\cdot \hat{j}$ (2)

Where:

$\|\vec F\|$ - Norm of the vector force, in newtons.

$\theta$ - Direction of the vector force with regard to the horizontal, in sexagesimal degrees.

$\hat{i}$ , $\hat{j}$ - Orthogonal axes, no unit.

If we know that $\|\vec F\| = 30\,lbf$ and $\theta = 25^{\circ}$ , then the force exerted on the wagon is:

Vector (ordered pair - rectangular form)

$\vec F= \left(30\cdot \cos 25^{\circ}, 30\cdot \sin 25^{\circ}\right)\,[lbf]$

$\vec F = (27.189,12.679)\,[lbf]$

Vector (ordered pair - polar form)

$\vec F = (30\,lbf, 25^{\circ})$

Sum of vectorial components (linear combination)

$\vec F = (30\cdot \cos 25^{\circ})\cdot \hat{i} + (30\cdot \sin 25^{\circ})\cdot \hat{j}\,[N]$

$\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]$

8 0

3 years ago

Find the common ratio for the following geometric sequence. <br><br> 2, 1, 0.5, 0.25, . . .

Oliga [24]

The common ratio is 2:1, or dividing by 2

3 0

3 years ago

Read 2 more answers

Find lim h→0 f(2+h)-f(2)/h if f(x)=x^2+x+1

bekas [8.4K]

Answer:

5

Step-by-step explanation:

$\displaystyle \lim_{h \to 0} \frac{f(2+h)-f(2)}{h}$

$\displaystyle\lim_{h \to 0} \frac{(2+h)^2 + 2 + h + 1 - 2^2 - 2 - 1}{h}$

$\displaystyle\lim_{h \to 0} \frac{4 + 4h + h^2 + h - 4}{h}$

$\displaystyle\lim_{h \to 0} \frac{h^2 + 5h}{h}$

$\displaystyle\lim_{h \to 0} h + 5$

= 5

8 0

3 years ago

Multiply:<br><br> (-4 + i)(-1 + 5i)

Olegator [25]

Answer:

$( - 4 + i) ( - 1 + 5i) \\ = 4 - 20i - 1i + 5 {i}^{2} \\ = 4 - ( -21i )+ 5i {}^{2}$

3 0

3 years ago

A man can buy 20 mangoes or 30 oranges. If he wants a each amount of each, how many of each would he get? Write an EQUATION to s

DochEvi [55]

Answer:

12

Step-by-step explanation:

In this question, there are two variables: the number of mangoes(y) bought and the number of oranges bought(x).

Let's say the man have z money, mangoes price is $\frac{1}{20}$ z and the oranges price is $\frac{1}{30}$ z. The equation for money and number of mangoes and oranges will be:

money = mango price * mangoes bought + orange price * orange bought

z= $\frac{1}{20}$ z * x + $\frac{1}{30}$ z *y

1= $\frac{1}{20}$ x + $\frac{1}{30}$ y

- $\frac{1}{30}$ y= $\frac{1}{20}$ x -1

y= -1.5x + 30

y= 30 - 1.5x

If he want equal number of mango and orange, that mean y=x. The calculation will be:

y= 30 - 1.5x

x= 30 - 1.5x

x+ 1.5x = 30

2.5x= 30

x= $\frac{30}{2.5}$ = 12

8 0

3 years ago