$2.72÷4====≠====================

Suppose that you need to build as many chairs as possible. Each chair requires one seat, one back, and four legs. If you have 12

GrogVix [38]

Answer:

legs limit the number of chairs that can be built

Step-by-step explanation:

The maximum number of chairs that can be built will be the minimum of the number of parts divided by the number of parts needed for each chair, as computed across the different kinds of parts required.

seats: 12 available, used 1 per chair: 12/1 = 12 chairs possible

backs: 15 available, used 1 per chair: 15/1 = 15 chairs possible

legs: 44 available, used 4 per chair: 44/4 = 11 chairs possible

The maximum number of chairs that can be built will be the minimum of 12, 15, and 11. That is, 11 chairs can be built, limited by the number of available legs.

6 0

2 years ago

X^2 +6x+30 in vertex form

Elina [12.6K]

Answer:

Step-by-step explanation:

Factoring x2-6x-30

The first term is, x2 its coefficient is 1 .

The middle term is, -6x its coefficient is -6 .

The last term, "the constant", is -30

Step-1 : Multiply the coefficient of the first term by the constant 1 • -30 = -30

Step-2 : Find two factors of -30 whose sum equals the coefficient of the middle term, which is -6 .

-30 + 1 = -29

-15 + 2 = -13

-10 + 3 = -7

-6 + 5 = -1

-5 + 6 = 1

-3 + 10 = 7

-2 + 15 = 13

-1 + 30 = 29

7 0

3 years ago

Read 2 more answers

NEED CORRECT ANSWER...

Misha Larkins [42]

39.50-23.76-2.57-1.49=11.68

take the sales and subtract the expenses

6 0

3 years ago

Which of the following are considered skew lines?

Gennadij [26K]

The answer is AE and GH

6 0

3 years ago

Suppose $1000 is invested at a rate of 13% per year compounded monthly. (Round your answers to the nearest cent.)

masya89 [10]

Answer:

a. $1010.83

b.$1066.77

c. $1138.00

d.$13,269.22

Step-by-step explanation:

Given the annual rate as 13%(compounded monthly) and the principal amount as $1000.

a. #first we calculate the effective annual rate;

$i_m=(1+i/m)^m-1\\\\i_{12}=(1+0.13/12)^{12}-1=0.1380$

The compounded amount after 1 month is therefore:

$P_1=P(1+I_m)^n, n=1/12, i_m=0.1380, P=1000\\\\P_1=1000(1+0.1380)^{1/12}\\\\P_1=1010.83$

Hence, the principle after one month is $1010.83

b. The principal after 6 months:

-From a above we have the effective annual rate as 0.1380 and our time is 6 months:

$P_{6m}=P(1+i_m)^n, \ n=6m, P=1000, i_m=0.1380\\\\P_{6m}=1000(1+0.1380)^{6/12}\\\\=1066.77$

Hence, the principal after 6 months is $1066.77

c.The principal after 1 year:

-From a above we have the effective annual rate as 0.1380 and our time is 12 months:

$P_{1y}=P(1+I_m)^n, n=1/12, i_m=0.1380, P=1000\\\\P_{1y}=1000(1+0.1380)^{12}\\\\P_{1y}=1138$

Hence, the principal after 1 year is $1138.00

d. The principal after 20years:

-From a above we have the effective annual rate as 0.1380 and our time is 20yrs:

$P_{20y}=P(1+I_m)^n, n=1/12, i_m=0.1380, P=1000\\\\P_{20y}=1000(1+0.1380)^{12}\\\\P_{20y}=13269.22$

Hence, the principal after 20 years is $13,269.22

3 0

3 years ago