<span>Part A: Area = length * width = (6x^2 + 3x - 2) * (x^3 - 2x + 5)
Multiply it out and simplify.
part B: </span><span>Take the first term 6x^2 and multiply each of the term x^3, -2x & 5. Then take 3x and multiply each of the term x^3, -2x & 5. Do the same with -2.
Then add like terms and simplify.</span>
Answer:
2
Step-by-step explanation:
f = a
48 = 3
32 = x
48x= 98
<u>x=2</u>
<h2><u>
Mark me as brainiest if i helped you </u></h2>
We have been given that the inverse variation
shows the relationship between wavelength in meters, x, and frequency, y. We are asked to find the wavelength for radio waves with frequency
.
To find the required wavelength, we substitute
in our given equation and solve for x as:


We can see that both numerator and denominator has 3, so we can cancel it out.

Using quotient rule of exponents
, we will get:


Therefore, the wavelength for radio waves would be
meters and option B is the correct choice.
Answer:
Step-by-step explanation:
a. sin^-1(sin theta) = theta
(1/sin)(sin theta) = theta
<em>the sines cross out</em> theta = theta
b. cos(cos^-1x) = x
cos(x/cos) = x
<em>the cosines cross out </em>x = x