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3 years ago

2(3-p)=17=41 show answer.

Mathematics

1 answer:

wolverine [178]3 years ago

6 0

this is what I found hope its correct!‍♀️

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If I have to move the constant over to one side, what value would I have to add to the left side in order to complete the square

trapecia [35]

Answer:

To make the equation complete square , we have to add 11 .

Step-by-step explanation:

Given as :

The linear equation is

x² + 4 x - 5 = 2

Now, move the constant to left side of equation

So, x² + 4 x - 5 - 2 = 0

Or, x² + 4 x - 7 = 0

<u>Now, to make equation complete square , let add 11 both side</u>

So, x² + 4 x - 7 + 11 = 11

Or, x² + 4 x + 4 = 11

Now, applying mid-term break

So, x² + 2 x + 2 x + 4 = 11

Or, x ( x + 2) + 2 (x + 2) = 11

Or, (x + 2) ( x + 2) = 11

Or, (x + 2)² = 11

Hence, To make the equation complete square , we have to add 11 . Answer

6 0

3 years ago

What is the equation of the line that passes through the point (6, -7) and has a<br> slope of - ?

mina [271]

Answer:

-1/2

Step-by-step explanation:

Teacher went through it with us in class.

3 0

3 years ago

Write an equation in slope-intercept form for the line passing through the pair of points.

yawa3891 [41]

Answer:

Step-by-step explanation:

use the slope formula to find the slope. y2-y1/x2-x1. 3-(-6)/-4-2 which is 9/-6 (subtracting a negative number is the same as adding a positive) which can be simplified to -3/2 which is the slope. the intercept is the point where y is at x=0, we already know at y=3 x is -4 from the second point, so the y intercept has to be -3. which can be proven by replacing the x and y with a point 3 = -3/2(-4) - 3. put -3/2 times 4 into a calculator and you get 6, 6-3 is 3 which makes the statement true.

7 0

3 years ago

When constructing an inscribed polygon with a compass and a straightedge, how should I start the construction?

lisabon 2012 [21]

I would say C, because it makes the most sense

3 0

4 years ago

What is the Inequality for this graph?

mote1985 [20]

Given:

The graph of an inequality.

To find:

The inequality for the given graph.

Solution:

From the given graph it is clear that the boundary line passes through the points (6,0) and (0,-4). So, the equation of the line is

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$

$y-0=\dfrac{-4-0}{0-6}(x-6)$

$y=\dfrac{-4}{-6}(x-6)$

$y=\dfrac{2}{3}(x-6)$

$y=\dfrac{2}{3}x-4$

The area under the boundary line is shaded and boundary line is a dotted line it means the points on the line are not included in the solution set. So, the inequality sing must be <.

$y$

Therefore, the required inequality for the given graph is $y$ .

8 0

3 years ago