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2 years ago

The sum of two numbers is 64 and their differences in 10. Find the numbers

Mathematics

2 answers:

patriot [66]2 years ago

8 0

Answer:

37 & 27

Step-by-step explanation:

x + y = 64

x - y = 10

=> 2x = 74

=> x = 37

x + y = 64

=> 37 + y = 64

=> y = 64 - 37

=> y = 27

uranmaximum [27]2 years ago

4 0

Answer:

37 and 27

Step-by-step explanation:

Lets say that the two numbers are x and y. We get the equations x + y = 64 and x - y = 10. We can then add these two equations together to get, 2x = 74. Then we divide by two on both sides and get x = 37. We then plug this value back into the second equation and get that 37 - y = 10. We can simplify this and we get that y = 27. So our two numbers are 37 and 27.

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2 years ago

Read 2 more answers

A population has a standard deviation of 5.5. What is the standard error of the sampling distribution if the sample size is 81?

VladimirAG [237]

Answer:

$\sigma = 5.5$

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution $\bar X$ and for this case we know that the distribution is given by:

$\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611$

Step-by-step explanation:

For this case we know the population deviation given by:

$\sigma = 5.5$

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution $\bar X$ and for this case we know that the distribution is given by:

$\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611$

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2 years ago

How many times the size of 0.81 is 810

MAXImum [283]

Answer:

810 is 100 times the size of 0.81

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2 years ago