Answer:
2 sqrt(3) -2i
Step-by-step explanation:
If we have the magnitude and the theta
z = |z| cos theta + i |z| sin theta
= 4 cos 330 + i 4 sin 330
=4 (sqrt(3)/2) + 4i (-1/2)
= 2 sqrt(3) -2i
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Answer: 3y = 2(x - 5)--------------------------------------------------------
Answer:
Your correct and final answer is (9+x^6) (3+x^3) (3-x^3)
Hope this helps!!!
Answer:
Option D (7).
Step-by-step explanation:
The formula for gradient of the straight line is given by:
m = (y2 - y1)/(x2 - x1); where (x1, y1) and (x2, y2) are two fixed points on the straight line. It is given that (x1, y1) = (4, r) and (x2, y2) = (r, 2). The gradient of the straight line is given by -5/3. To find the value of r, simply substitute all the values in the gradient equation. Therefore:
-5/3 = (2 - r)/(r - 4).
Cross Multiplying:
-5*(r - 4) = 3*(2 - r).
-5r + 20 = 6 - 3r.
-2r = -14.
r = 7.
Therefore, Option D is the correct answer!!!
