What are you trying to do here?
Solve the graph, or make it appear as something else?
First, we're going to take one sec (x) out so that we get:
sec (x) (2sec (x) -1 -1) = 0
sec (x) (2sec (x) -2) = 0
Then we're going to separate the two to find the zeros of each because anything time 0 is zero.
sec(x) = 0
2sec (x) - 2 = 0
Now, let's simplify the second one as the first one is already.
Add 2 to both sides:
2sec (x) = 2
Divide by 3 on both sides:
sec (x) = 1
I forgot my unit circle, so you'd have to do that by yourself. Hopefully, I helped a bit though!
9 is the answer negatives cancel out creating positve
Step-by-step explanation:
given,
x1= 1 , x2= 7 , m1= 3
y1= 4 , y2= 1 , m2= 1
x=?
y=?
using section formula
x= (m2.x1 + m1.x2)/m1 + m2
x= find yourself
y= (m2.y1 + m1.y2) / m1 + m2
y= find yourself
You should go up 3.5 on the Y-Axis and then go up .5 and over 1.
