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alexgriva [62]
4 years ago
13

Please answer this correctly

Mathematics
2 answers:
skelet666 [1.2K]4 years ago
6 0

Answer:

80-119 ⇒ 5

Because

80-99 ⇒ 3

100-119 ⇒ 2

So 2+3 = 5

german4 years ago
6 0

Answer:

80-119: 5

Step-by-step explanation:

If you just added up, you can find all the values.

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N-2÷7=2 ANSWER IT 50 POINTS
Marianna [84]

Answer:

5.5

Step-by-step explanation:

n-2÷7=2

n-3.5=2

n=2+3.5

n=5.5

6 0
4 years ago
Read 2 more answers
519 divided by 6 and 915 divided by 7 and 439 divided by 7 and 812 divided by 9 which one does not have a two digit quotient.
Setler [38]

519/6=86.5

915/7=130.7142

439/7=62.7142

812/9=90.2222

so i think its the 1st on but i may be wrong.

5 0
3 years ago
To describe a sequence of transformations that maps triangle ABC onto triangle A"B"C", a student starts with a reflection over t
inysia [295]

Answer:

To describe a sequence of transformations that maps triangle ABC onto triangle A"B"C", a student starts with a reflection over the x-axis. The student student complete the sequence of transformations to map triangle ABC to triangle A"B"C" is by translating the figure 2 units to the right. Translate the figure 6 units up.

6 0
3 years ago
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Simplify (6m2-5m+4)+(7m2+2m-5)
laiz [17]

Answer:13m2 - 3m - 1 i think that is the answer


Step-by-step explanation:


8 0
3 years ago
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Consider the probability that fewer than 26 out of 107 cell phone calls will be disconnected. Assume the probability that a give
anyanavicka [17]

Answer:

We assume the condition of independence satisifed.

We need to check the following conditions in order to use the normal approximation.

np=107*0.98=104.86 \geq 10

n(1-p)=107*(1-0.98)=2.14 < 10

So we see that we satisfy the first condition, but the second no so then we can't apply the approximation for this case, since we need both conditions at the same time in order to use the normal approximation.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=107, p=0.98)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

Solution to the problem

We assume the condition of independence satisifed.

We need to check the following conditions in order to use the normal approximation.

np=107*0.98=104.86 \geq 10

n(1-p)=107*(1-0.98)=2.14 < 10

So we see that we satisfy the first condition, but the second no so then we can't apply the approximation for this case, since we need both conditions at the same time in order to use the normal approximation.

4 0
3 years ago
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