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svet-max [94.6K]
3 years ago
15

Equation of a circle whose center is at (4,0) and radius is length 2/3

Mathematics
1 answer:
Masteriza [31]3 years ago
5 0
We need (x-h)^2 + (y-k)^2 = r^2

h = 4, k = 0 and r = 2/3

Take it from here.
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In Sarah‘s dance class 1/16 of the girls are also on the soccer team. what is the decimal form of this fraction
Alenkasestr [34]

Answer:0.0625


Step-by-step explanation:


5 0
3 years ago
Ann wants to choose from two telephone plans. Plan A involves a fixed charge of $10 per month and call charges at $0.10 per minu
Kay [80]
Ann wants to choose from two telephone plans. Plan A involves a fixed charge of $10 per month and call charges at $0.10 per minute. Plan B involves a fixed charge of $15 per month and call charges at $0.08 per minute.

Plan A $10 + .10/minute

Plan B $15 + .08/minute

If 250 minutes are used:

Plan A: $10+$25=$35
Plan B: $15+$20=$35

If 400 minutes are used:

Plan A: $10+$40=$50
Plan B: $15+$32=$47

B is the correct answer. How to test it:

Plan A: $10+(.10*249 minutes)
$10+$24.9=$34.9

Plan B: $15+(.08*249 minutes)
$15+$19.92=$34.92

Plan A < Plan B if less than 250 minutes are used.
4 0
3 years ago
What is 2 3/8 in a improper fraction?
FromTheMoon [43]

Answer:

See below a shorter way to convert 2 3 8 to an improper fraction. Step 1: Multiply the whole number part (2) by the denominator (8). Step 2: Add the product from Step 1 (16) to the numerator (3). Step 3: Write that result (19) above the denominator.

Step-by-step explanation:

hope this helps you if it does plz mark brainiest

4 0
3 years ago
Read 2 more answers
I need help like fast i am on 3 and i do not know what to do
Elis [28]

Answer:

Number 3 has no solution

Step-by-step explanation:

First you need to divide both sides of the equation 12x - 12y = -12 by 4

-3x + 3y = -3

12x - 12y = -12

-3x + 3y = -3

3x - 3y = -3

Then you need to eliminate one variable by adding the equations.

0 = -6

this statement is false, and therefore has no solution.

7 0
3 years ago
1/ab + a^2/b^2 <br> find the sum?
maxonik [38]

\dfrac 1{ab} + \dfrac{a^2}{b^2}\\\\\\=\dfrac{b+a^3}{ab^2}\\\\\\=\dfrac{a^3 +b}{ab^2}

7 0
2 years ago
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