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svet-max [94.6K]
3 years ago
15

Equation of a circle whose center is at (4,0) and radius is length 2/3

Mathematics
1 answer:
Masteriza [31]3 years ago
5 0
We need (x-h)^2 + (y-k)^2 = r^2

h = 4, k = 0 and r = 2/3

Take it from here.
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Solve the equation x³ − 5 = 59
In-s [12.5K]

Answer:

4 = x

Step-by-step explanation:

x³ - 5 = 59     Add five to both sides of the equation.

x³ = 64          Now find the cubed root of 64

∛64 = 4

x = 4

3 0
3 years ago
Help the question is in the picture please help help
Reika [66]
I just tried to help someone with the same problems. I hope this helps you

7 0
3 years ago
Suppose that an object moves along the y-axis so that its location is y=x2+3x at time x. (Here y is in meters and x is in second
vfiekz [6]

Answer:

a) 13 m/s

b) (15  + h) m/s

c) 15 m/s

Step-by-step explanation:

if the location is

y=x²+3*x

then the average velocity from 3 to 7 is

Δy/Δx=[y(7)-y(3)]/(7-3)=[7²+3*7- (3²+3*3)]/4= 13 m/s

then the average velocity from x=6 to to x=6+h

Δy/Δx=[y(6+h)-y(6)]/(6+h-6)=[(6+h)²+3*(6+h)- (6²+3*6)]/h= (2*6*h+3*h+h²)/h=2*6+3= (15 + h) m/s

the instantaneous velocity can be found taking the limit of Δy/Δx when h→0. Then

when h→0 , limit Δy/Δx= (15 + h) m/s = 15 m/s

then v= 15 m/s

also can be found taking the derivative of y in x=6

v=dy/dx=2*x+3

for x=6

v=dy/dx=2*6+3 = 12+3=15 m/s

7 0
3 years ago
Question 2
SCORPION-xisa [38]
Where are the choices
4 0
3 years ago
The function f(x) is an increasing function about which little else is known about other than f(2)=7 and f'(2)=5. Find (f^-1)'(7
andreyandreev [35.5K]

Since f(x) is (strictly) increasing, we know that it is one-to-one and has an inverse f^(-1)(x). Then we can apply the inverse function theorem. Suppose f(a) = b and a = f^(-1)(b). By definition of inverse function, we have

f^(-1)(f(x)) = x

Differentiating with the chain rule gives

(f^(-1))'(f(x)) f'(x) = 1

so that

(f^(-1))'(f(x)) = 1/f'(x)

Let x = a; then

(f^(-1))'(f(a)) = 1/f'(a)

(f^(-1))'(b) = 1/f'(a)

In particular, we take a = 2 and b = 7; then

(f^(-1))'(7) = 1/f'(2) = 1/5

3 0
2 years ago
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