Let a =107° and b=42°;
So cos 107° cos 42° + sin 107° sin 42° = cosa.cos42 + sina.sinb = cos(a-b)
and cos 107° cos 42° + sin 107° sin 42° = cos(107-42) = cos(65°)
The circumference is greater than 33 centimeters, it stands somewhere around 11 π.
Answer:
A. 2·x² + 16·x + 32 ≥ 254
Step-by-step explanation:
The given dimensional relationship between the dimensions of the photo in the center of the cake and the dimensions of the cake are
The width of the cake = The width of the photo at the center of the cake, x + 4 inches
The length of the cake = 2 × The width of the cake
The area of the cake Wanda is working on ≥ 254 in.²
Where 'x' represents the width of the photo (at the center of the cake), let 'W' represent the width of the cake, let 'L' represent the length of the cake, we get;
W = x + 4
L = 2 × W
Area of the cake, A = W × L ≥ 254
∴ A = (x + 4) × 2 × (x + 4) = 2·x² + 16·x + 32 ≥ 254
The inequality representing the solution is therefore;
2·x² + 16·x + 32 ≥ 254
Basically the question is asking if the proportions for the dimensions of the 2 rugs are the same, so in this case yes, since 6 X 8 can be written as 3 X 4 which if you set up a fraction you can easily multiply both the top and bottom number by 3 to get 9 X 12.
Answer:
<h3>Princeton Florist</h3>
Let the total charge is y, the number of small arrangements is x.
<u>Total charge will be:</u>
<h3>Chad's Flowers</h3>
<u>Total charge will be:</u>
<u>Since the total charge is same in both shops, we have:</u>
<u>Solve for x:</u>
- 17x - 13x = 47 - 35
- 4x = 12
- x = 3
<u>Total cost is:</u>
<u>Small arrangements</u> = 3, <u>cost </u>= $86
