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marin [14]
3 years ago
11

Which expression is equivalent to ^3 square root 64a^6 b^7 c^9

Mathematics
2 answers:
sergij07 [2.7K]3 years ago
7 0

Answer:

4a^{2} b^{2} c^{3} (\sqrt[3]{b})

Step-by-step explanation:

The given expression is :

\sqrt[3]{(64}a^{6}b^{7} c^{9} )

Writing 64 ,a,b,c as cubes we have:

= \sqrt[3]{(}4^{3}( a^{2})^3( b^{2})^3.b( c^{3} )^3)

Using radical rule we have :

=4a^{2} b^{2} c^{3} (\sqrt[3]{b}).

The second option is the right answer.



noname [10]3 years ago
3 0

Answer:

\sqrt[3]{64a^6b^7c^9}\Rightarrow 4a^2b^2c^3\sqrt[3]{b}.

Option 2 is correct.

Step-by-step explanation:

Given: \sqrt[3]{64a^6b^7c^9}

We need to simplify the complex radical and to compare with given options which is equivalent to this.

\Rightarrow \sqrt[3]{64a^6b^7c^9}

separate the radical 3 with each term inside the radical.

\Rightarrow \sqrt[3]{64}\cdot \sqrt[3]{a^6}\cdot \sqrt[3]{b^7}\cdot \sqrt[3]{c^9}

Simplify each radical

\Rightarrow 4\cdot a^2\cdot b^2\sqrt[3]{b}\cdot c^3

Write all term together

\Rightarrow 4a^2b^2c^3\sqrt[3]{b}

Hence, The equivalent expression \Rightarrow 4a^2b^2c^3\sqrt[3]{b}

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Answer:

25%

Step-by-step explanation:

If we consider the original price of the piece of suit is x.

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Now, the price of the suit on Tuesday was changed back to the original price i.e. x.

Therefore, the price is increase by (x - 0.8x) = 0.2x from the price of 0.8x.

So, the percentage change in price of the suit on Tuesday is \frac{0.2x}{0.8x} \times 100 = 25%. (Answer)

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3 years ago
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Daniel [21]

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Step-by-step explanation:

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Let f(x) = twenty-four over the quantity of 3 x minus two. Find f(-2
bija089 [108]
f(x)=\frac{24}{3x-2}\\\\f(-2)=?\\
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Read 2 more answers
A bridge in the shape of an arch connects two cities separated by a river. The two ends of the bridge are located at (–7, –13) a
sdas [7]

Answer:

y=-\dfrac{13}{49}x^2

Step-by-step explanation:

The shape of an arch corresponds to a parabola.

the general equation for a parabola is:

y=ax^2+bx+c

we're given three coordinates: (-7,-13),(7,-13) and (0,0)

so we can plug these values in the general equation to make 3 separate equations:

(x,y) = (-7,-13)

-13=a(-7)^2+b(-7)+c

49a-7b+c=-13

(x,y) = (7,-13)

-13=a(7)^2+b(7)+c

49a+7b+c=-13

(x,y) = (0,0)

0=a(0)^2+b(7)+c

c=0

so we have three equations. and we can solve them simultaneously to find the values of a,b, and c.

we've already found c = 0, let's use substitute it to other equations.

49a-7b+c=-13\quad\Rightarrow\quad49a-7b=-13

49a+7b+c=-13\quad\Rightarrow\quad49a+7b=-13

we can solve these two equation using the elimination method, by simply adding the two equations

\quad\quad49a-7b=-13\\+\quad49a+7b=-13

------------------------------

\quad\quad 98a=-26

\quad\quad a=-\dfrac{13}{49}

Now we can plug this value of a in any of the two equations.

49a-7b=-13

49\left(-\dfrac{13}{49}\right)-7b=-13

-13-7b=-13

-7b=0

b=0

We have the values of a,b, and c. We can plug them in the general equation to find the equation of the arch.

y=\left(-\dfrac{13}{49}\right)x^2+0x+0

y=-\dfrac{13}{49}x^2

49y=-13x^2

This our equation of the arch!

5 0
3 years ago
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Answer:

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7 0
3 years ago
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