Answer:
Lactose is more likely to be utilised by E. Coli than Arabinose because Lactose will yield more energy (ATP) and lactose breakdown will give glucose and galactose and these will enter into the glycolytic pathways to pyruvate for ATP generation until Arabinose which will undergo Pentose phosphate pathway and this does not produce enough energy.
Answer:
glomerulus and glomerular capsule.
Explanation:
Carbohydrate is the answer
Answer:
Cytokinesis
Explanation:
It is the first stage
Answer:
black carbon which is "B"
