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Usimov [2.4K]
3 years ago
11

Find the equation of the line specified.

Mathematics
2 answers:
torisob [31]3 years ago
7 0

m =  \frac{ - 5 + 7}{6 - 7}  \\  \frac{2}{ - 1}  =  - 2 \\ y + 5 =  - 2(x - 6) \\ y + 5 =  - 2x + 12 \\ y =  - 2x + 7
A.
Radda [10]3 years ago
3 0

Answer:

A

Step-by-step explanation:

i did the practice and got it right :)

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A cubical tank of edge 12 cm is half filled with water. The water is poured into an empty rectangular tank measuring 10 cm by 8
qaws [65]

Answer:

3040000mm³

Step-by-step explanation:

Volume of a cube = a³ ; a = size of edge

Volume of cubical tank = 12³ = 12 * 12 * 12 = 1728 cm³

Half filled cube = 1728 / 2 = 864 cm³

Volume is f rectangular tank :

V = length * width * height

V = 10 * 8 * 7 = 560 cm³

Volume of water left in cubical tank :

(864 - 560) = 304cm³

1cm³ = 1000mm³

304cm³ = 304 * 1000 = 3040000mm³

3 0
3 years ago
Kareem has a collect of dimes and quarters. He can tell that he has more quarters than dimes, and he knows that he has at most $
Mariulka [41]

Answer:

D<Q≤2 Or D<Q Q+D≤2

Step-by-step explanation:

I'm pretty sure this is the answer but it's been a while since I've done system of inequalities. Essentially the value and number of dimes is less than the value and number of quarters. And the value of both is less than or equal to 2 dollars

8 0
3 years ago
Find the square of<br>i) a+ X<br>ii). b-y<br>​
deff fn [24]

Right now, x is only equal to two. Square both sides, and x^2 = 4. For some reason, if you want to take the square root of both sides, and you get x= +/- 2, ...

7 0
2 years ago
Find the local max and min values of f(x)=x^2/x-1 using both first and second derivative tests
uranmaximum [27]
Hmm, the 2nd derivitve is good for finding concavity

let's find the max and min points
that is where the first derivitive is equal to 0
remember the difference quotient

so
f'(x)=(x^2-2x)/(x^2-2x+1)
find where it equals 0
set numerator equal to 0
0=x^2-2x
0=x(x-2)
0=x
0=x-2
2=x

so at 0 and 2 are the min and max
find if the signs go from negative to positive (min) or from positive to negative (max) at those points

f'(-1)>0
f'(1.5)<0
f'(3)>0

so at x=0, the sign go from positive to negative (local maximum)
at x=2, the sign go from negative to positive (local minimum)


we can take the 2nd derivitive to see the inflection points
f''(x)=2/((x-1)^3)
where does it equal 0?
it doesn't
so no inflection point
but, we can test it at x=0 and x=2
at x=0, we get f''(0)<0 so it is concave down. that means that x=0 being a max makes sense
at x=2, we get f''(2)>0 so it is concave up. that means that x=2 being a max make sense




local max is at x=0 (the point (0,0))
local min is at x=2 (the point (2,4))
6 0
3 years ago
The expanded form of an expression is 1/bbb What is the equivalent expression in exponential form?
4vir4ik [10]

Answer:

my meat is starting to shrink

Step-by-step explanation:

jack off for for two straight months (especially if you're a girl)

6 0
3 years ago
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