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Usimov [2.4K]
3 years ago
11

Find the equation of the line specified.

Mathematics
2 answers:
torisob [31]3 years ago
7 0

m =  \frac{ - 5 + 7}{6 - 7}  \\  \frac{2}{ - 1}  =  - 2 \\ y + 5 =  - 2(x - 6) \\ y + 5 =  - 2x + 12 \\ y =  - 2x + 7
A.
Radda [10]3 years ago
3 0

Answer:

A

Step-by-step explanation:

i did the practice and got it right :)

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daser333 [38]
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6 0
3 years ago
Read 2 more answers
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Julli [10]

Answer:

→ The table is:

→  x  →  -1   →  0  →  1

→  y  →  -3  →  0  →  3

The graph of the line is figure d

Step-by-step explanation:

∵ y = 3x

∵ x = -1, 0, 1

→ Substitute the values of x in the equation to find the values of y

∴ y = 3(-1) = -3

∴ y = 3(0) = 0

∴ y = 3(1) = 3

→ The table is:

→  x  →  -1   →  0  →  1

→  y  →  -3  →  0  →  3

∵ The form of the linear equation is y = m x + b, where

  • m is the slope
  • b is the y-intercept

∵ y = 3x

→ Compare the equation with the form

∴ m = 3

∴ b = 0

→ That means the slope is positive, then the direction of the line must

   be from left tp right and passes through the origin

∴ The graph of the line is figure d

6 0
3 years ago
Triangle ABC has vertices at A(2,3),B(-4,-3) and C(2,-3) find the coordinates of each point of concurrency.
dem82 [27]

Answer:

Circumcenter =(-1,0)

Orthocenter =(2,-3)

Step-by-step explanation:  

Given : Points A = (2,3), B = (-4,-3), C = (2,-3)  

Formula used :  

→Mid point of two points- (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

→Slope of two points - \frac{y_2-y_1}{x_2-x_1})

→Perpendicular of a line = \frac{-1}{slope of line})

Circumcenter- The point where the perpendicular bisectors of a triangle meets.

Orthocenter-The intersecting point for all the altitudes of the triangle.

To find out the circumcenter we have to solve any two bisector equations.

We solve for line AB and AC

So, mid point of AB =(\frac{2-4}{2},\frac{3-3}{2})=(-1,0)

Slope of AB =\frac{-3-3}{-4-2}=1

Slope of the bisector is the negative reciprocal of the given slope.  

So, the slope of the perpendicular bisector = -1  

Equation of AB with slope -1 and the coordinates (-1,0) is,  

(y – 0) = -1(x – (-1))  

y+x=-1………………(1)  

Similarly, for AC  

Mid point of AC = (\frac{2+2}{2},\frac{3-3}{2})=(2,0)

Slope of AC = \frac{-3-3}{2-2}=\frac{-6}{0}  

Slope of the bisector is the negative reciprocal of the given slope.  

So, the slope of the perpendicular bisector = 0  

Equation of AC with slope 0 and the coordinates (2,0) is,  

(y – 0) = 0(x – 2)  

y=0 ………………(2)  

By solving equation (1) and (2),  

put y=0 in equation (1)

y+x=-1

0+x=-1

⇒x=-1  

So the circumcenter(P)= (-1,0)

To find the orthocenter we solve the intersections of altitudes.

We solve for line AB and BC

So, mid point of AB =(\frac{2-4}{2},\frac{3-3}{2})=(-1,0)

Slope of AB =\frac{-3-3}{-4-2}=1

Slope of the bisector is the negative reciprocal of the given slope.  

So, the slope of CF = -1  

Equation of AB with slope -1 and the coordinates (-1,0) gives equation CF  

(y – 0) = -1(x – (-1))  

y+x=-1………………(3)  

Similarly, mid point of BC =(\frac{-4+2}{2},\frac{-3-3}{2})=(-1,-3)

Slope of AB =\frac{-3+3}{-4-2}=0

Slope of the bisector is the negative reciprocal of the given slope.  

So, the slope of AD = 0

Equation of AB with slope 0 and the coordinates (-1,-3) gives equation AD

(y-(-3)) = 0(x – (-1))  

y+3=0

y=-3………………(4)  

Solve equation (3) and (4),

Put y=-3 in equation (3)

y+x=-1

-3+x=-1

x=2

Therefore, orthocenter(O)= (2,-3)


7 0
3 years ago
Find the value of q in the following system so that the solution to the system is(4,2) 3x-2y=8
Nataliya [291]
We have that
<span>3x-2y=8 -----> equation 1
2x+3y=Q----> equation 2

the solution is the point </span><span>(4,2)
in the equation 2 substitute the value of
x=4
y=2
so
</span>2x+3y=Q------> 2*4+3*2=Q-------> Q=8+6------> Q=14
<span>
the answer is
Q=14

</span>
3 0
3 years ago
Expand 2(x-1) <br> Expand 3(2x+3)<br> Expand 7(x+5) <br> Expand 5(2x-y)
Agata [3.3K]
Those are the answers
2x-2
6x+9
7x+35
10x-5y
7 0
2 years ago
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