Answer:
40
Step-by-step explanation:
32/80 = 0.4
0.4 x 100 = 40
2ty'=4y
Replacing y'=dy/dt in the equation:
2t(dy/dt)=4y
Grouping terms:
dy/y=4dt/(2t)
dy/y=2dt/t
Integrating both sides:
ln(y)=2ln(t)+ln(c), where c is a constant
Using property logarithm: b ln(a) = ln(a^b), with b=2 and a=t
ln(y)=ln(t^2)+ln(c)
Using property of logarithm: ln(a)+ln(b) = ln(ab), with a=t^2 and b=c
ln(y)=ln(ct^2)
Then:
y=ct^2
Using the initial condition: y(2)=-8
t=2→y=-8→c(2)^2=-8→c(4)=-8
Solving for c:
c=-8/4
c=-2
Then the solution is y=-2t^2
Comparing with the solution: y=ct^r
c=-2, r=2
Answer: T<span>he value of the constant c is -2 (c=-2) and the exponent r is 2 (r=2)</span>
Answer:
Throughout the clarification section elsewhere here, the definition of the concern is discussed.
Step-by-step explanation:
- This seems to be an experimental analysis where the students were purposely administered an assessment and treatment of someone using notecards towards examine a potential improvement in the answer or calculated indicator that is average scores.
- Overall test scores are the answer component.
- Through the use of notecards seems to be the explanatory component. The vector degree is 'Used' either 'Not Used.'
- The participants offering the test seem to be the experimental groups.
