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aalyn [17]
3 years ago
13

Can anyone solve this:

Mathematics
2 answers:
Law Incorporation [45]3 years ago
8 0

f(20) = 9204 * e^(.022*20)

f(20) = 14,291 hits

Note: 20 is the number of years after the year 2000 to get to 2020

ludmilkaskok [199]3 years ago
7 0
So fuctions mean
if
f(x)=x+2 then if you put in 3 for x then
f(3)=3+2=5 so

if x=years after 2000
in 2020 then
2020-2000=20 so x=20
subsitute
f(20)=9204e^0.022(20)

e could be:
1. common base of logarithms (memorised to 15 decmals) 2.718281828459045
2. a computer notation exg if you have 3e11 that means 3 times 10^11

if it is 1
9240 times (2.718281828459045^(0.022 times 20))=( simplify exponent first) 9240 times (2.718281828459045^0.44)=9204 times 1.5527072185113=14291.1 or rounded to 14291

if it is 2
9204 times 10^(0.022 times 20)=9204 times 10^(0.44)=9204 times 254.491 rounded to 254


so the answer dependes on what e represents,

if e is:
1. common base of logarithms (memorised to 15 decmals) 2.718281828459045, then answer is 14291

2. a computer notation exg if you have 3e11 that means 3 times 10^11 =254

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