If the speed is constant, there is no acceleration. No acceleration, no force.
So find the difference between 1995 and 2022 to make it easier
2022-1995=27
so the rephrased question is
when hazel was x years old, she was 25 years older than son gary who was y old at that time (equation is x is 25 more than y or x=25+y)
in 27 years, (this means x+27 and y+27) hazel's age will be 150% of gary's age (x+27= 150% of y+27)
percent means parts out of 100 so 150%=150/100=15/10=1.5
'of' in math means multiply so
the equations are
x=25+y
x+27=1.5(y+27)
subsitute 25+y for x in second euation
25+y+27=1.5(y+27)
add like terms
y+52=1.5(y+27)
I personally dislike decimals to multiply both sides by 2 to make 2 0.5's or 1 (you are technically supposed to distribute or divide both sides by 1.5) so
2y+104=3(y+27)
distribute
2y+104=3y+81
subtract 2y from both sides
104=y+81
subtract 81 from both sides
23=y
subsitute
x=25+y
x=25+23
x=48
Hazel was 48 and Gary was 23 in the year of 1995
Answer:
Step-by-step explanation:
4q2 + 2q + 3
(2q - 2) l _ 8q3 - 4q2 - q + 6
8q3 - 8q2
_ 4q2 - q
4q2 - 4q
_ 3q + 6
6q + 6
-3q (remainder)
4q2 + 2q + 3 -3q / (2q - 2)
hope this helps
It looks like the first 3 are because they all are blank x2.5 but the last one would be 8x2.5=20..
The distance, s = 40t₁ where t₁ is the time to complete the outward journey.
The same distance = vt₂ where t₂ is the time to complete the return journey at speed v.
For the whole journey, 2s=60(t₁+t₂). Therefore s=30(t₁+t₂)=40t₁=vt₂.
30t₁+30t₂=40t₁, 10t₁=30t₂, t₁=3t₂, so s=120t₂=vt₂ and v=120kph.
