The maximum height of the projectile is the maximum point that can be gotten from the projectile equation
The projectile reaches the maximum height after 5 seconds
The function is given as:
Differentiate the function with respect to t
Set to 0
So, we have:
Collect like terms
Solve for t
Hence, the projectile reaches the maximum after 5 seconds
Read more about maximum values at:
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Answer:
huh
Step-by-step explanation:
Answer:
the answer is "B" the second one...
(1/2)(2)^x
at
0 = (1/2)(1) = 1/2
2= (1/2)(4) = 2
Step-by-step explanation:
Equation 1: y = -2x + 1
Equation 2: y = 2x - 3
Since both equations already have y isolated, we are able to simply set the right side of both equations equal to each other. Since we know that the value of y must be the same, we can do this.
-2x + 1 = 2x - 3
1 = 4x - 3
4 = 4x
x = 1
Then, we need to plug our value of x back into either of the original two equations and solve for y. I will be plugging x back into equation 2 above.
y = 2x - 3
y = 2(1) - 3
y = 2 - 3
y = -1
Hope this helps!! :)
Answer:
336
Step-by-step explanation:
i hope i got it right
