All categories

3 years ago

Arnold can do 65 push-ups in 5 minutes. how many push-ups can he do in 1 minute?

Mathematics

1 answer:

djverab [1.8K]3 years ago

8 0

65 push-ups in 5 minutes.
Divide 65 by 5
65÷5=13
Arnold can do 13 push ups in 1 minutes.

You might be interested in

Determine the negation of the following statement:<br><br> x is not equal to 50.

Lana71 [14]

Any more details? I cannot know if you don’t have any more details for me

4 0

2 years ago

A biscuit recipe calls for 2 pounds of all purpose flour and .75 pound of butter, what would be the baker’s percentage for butte

Goryan [66]

Answer: 37.5%

Explanation:

Percentage is defined as parts of an amount in 100 parts of a basis. This must be stated mathamatically for better understanding and for calculations. It is the ratio:

% = (parts / base) × 100.

In this case you need to express the amount of butter as a part in 100 parts of all purpose flour, which, using the above definition, is:

% butter = (0.75 pounds of butter / 2 pound of flour) × 100

% butter = 0.75 × 100 / 2 = 75 / 2 = 37.5

The answer is expressed as 37.5%.

4 0

3 years ago

Ayaan travels 90 miles at an average speed of 60 mph. She then travels a further 40 miles. The average speed for the entire jour

SashulF [63]

Answer:

is 11.89

pa brainless na lng po

7 0

2 years ago

Which decimal is equivalent to 3/16

mrs_skeptik [129]

0.1875

Hope you score well

Have. Good day!

8 0

3 years ago

A new shopping mall records 120 total shoppers on their first day of business. Each day after that, the number of shoppers is 10

Iteru [2.4K]

Answer:

$1,139\ shoppers$

Step-by-step explanation:

we know that

In this problem we have a exponential function of the form

$y=a(b)^{x}$

where

a is the initial value or y-intercept

b is the base of the exponential function

r is the rate in decimal form

b=(1+r)

In this problem we have

x ----> the number of days

y ----> the number of shoppers

a=120

r=10%=10/100=0.10

b=1+0.10=1.10

substitute the values

$y=120(1.10)^{x}$

First day

$y=120$

Second day

For x=1 day

substitute the value of x in the equation and solve for y

$y=120(1.10)^{1}=132$

Third day

For x=2 days

$y=120(1.10)^{2}=145$

Fourth day

For x=3 days

$y=120(1.10)^{3}=160$

Fifth day

For x=4 days

$y=120(1.10)^{4}=176$

Sixth day

For x=5 days

$y=120(1.10)^{5}=193$

Seventh day

For x=6 days

$y=120(1.10)^{6}=213$

Adds the numbers

$120+132+145+160+176+193+213=1,139$

3 0

3 years ago

Read 2 more answers