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3 years ago

HELP PLS! asap!! what is the resulting ordered pair if the value of the independent variable is 5?

Mathematics

2 answers:

Serga [27]3 years ago

6 0

Independent variable is 5 means x = 5
solve for f(x) when x = 5
f(5) = -2(5) +1
f(5) = -10 + 1
f(5) = -9

Solution (5,-9)

Answer
B. (5,-9)

Mashutka [201]3 years ago

6 0

Answer b for sure !!!!!

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Dominic answered 43 of the 50 questions on his spelling test correctly. Which decimal represents the fraction of problems he ans

sertanlavr [38]

Answer:

0.86

Explanation:

He answered 43 out of 50 questions.

As a fraction this is written

To convert this fraction to a decimal fraction divide 43 by 50 .This

can be done on a calculator to obtain 0.86

Step-by-step explanation:

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3 years ago

Exercise 2.2 gave the following data (in increasing order) for the attribute age: 13, 15, 16, 16, 19, 20, 20, 21, 22, 22, 25, 25

Mazyrski [523]

Answer:

Step-by-step explanation:

13, 15, 16, 16, 19, 20, 20, 21, 22, 22, 25, 25, 25, 25, 30, 33, 33, 35, 35, 35, 35, 36, 40, 45, 46, 52, 70.

a) Smoothing by bin means

Each bin has depth of 3

Dividing data into bins

so, Bin 1= 13, 15, 16

Bin 2= 16, 19, 20

Bin 3= 20, 21, 22

Bin 4= 22, 25, 25

Bin 5= 25, 25, 30

Bin 6= 33, 33, 35

Bin 7 = 35, 35, 35

Bin 8= 36, 40, 45

Bin 9= 46, 52, 70

Now, smoothing data by bin mean

so, Bin 1= 13, 15, 16 = (13+15+16)/3 = 15 Bin 1 = 15,15,15

Bin 2= 16, 19, 20 = (16+19+20)/3 = 18 Bin 2 = 18,18,18

Bin 3= 20, 21, 22= (20+21+22)/3 = 21 Bin 3 = 21,21,21

Bin 4= 22, 25, 25 = (22+25+25)/3 = 24 Bin 4 = 24,24,24

Bin 5= 25, 25, 30 =(25+25+30)/3 = 27 Bin 5 = 27,27,27

Bin 6= 33, 33, 35 = (33+33+35)/3 = 34 Bin 6 = 34,34,34

Bin 7 = 35, 35, 35 = (35+35+35)/3 = 35 Bin 7 = 35,35,35

Bin 8= 36, 40, 45 = (36+40+45)/3 = 40 Bin 8 = 40,40,40

Bin 9= 46, 52, 70=(46+52+70)/3 = 56 Bin 9 = 56,56,56

This technique is used to smooth the data. Data may have noise, using binning techniques we can remove noise from the data. It helps in providing more accurate results

b) How might you determine outliers in the data?

Outliers are the data that are abnormal to other data points. Outliers can be found by Box and whisker chart (box plot). Inter Quartile range can also be used to identify outliers

c) What other methods are there for data smoothing?

Other methods of smoothing data are

a) binning by boundaries

b) Exponential smoothing

c) Random walk

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3 years ago

A production manager at a wall clock company wants to test their new wall clocks. The designer claims they have a mean life of 1

Harman [31]

The probability that the mean clock life would differ from the population mean by greater than 12.5 years is 98.30%.

Given mean of 14 years, variance of 25 and sample size is 50.

We have to calculate the probability that the mean clock life would differ from the population mean by greater than 1.5 years.

μ=14,

σ= $\sqrt{25}$ =5

n=50

s orσ =5/ $\sqrt{50}$ =0.7071.

This is 1 subtracted by the p value of z when X=12.5.

So,

z=X-μ/σ

=12.5-14/0.7071

=-2.12

P value=0.0170

1-0.0170=0.9830

=98.30%

Hence the probability that the mean clock life would differ from the population mean by greater than 1.5 years is 98.30%.

Learn more about probability at brainly.com/question/24756209

#SPJ4

There is a mistake in question and correct question is as under:

What is the probability that the mean clock life would differ from the population mean by greater than 12.5 years?

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