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3 years ago

Suppose a circle and a line intersect in a plane what is the smallest number of points at which they can touch

Mathematics

2 answers:

Anna35 [415]3 years ago

8 0

The smallest amount of points at which they could intersect is 2.

worty [1.4K]3 years ago

5 0

Answer:

The smallest number of points at which they can touch is 1.

Step-by-step explanation:

You might be interested in

Y-intercept. y = -3/2x

Vaselesa [24]

Answer:

i hope you find the answer but unfortunaatly im not sure

Step-by-step explanation: thankyou for the points though :)

3 0

2 years ago

2 over 5 (x − 4) = 2x.

Sav [38]

2/5 (x-4)=2x answer is x= -1

5 0

2 years ago

(x+1)^2+(x-1)^2-2x(x+2)=0

antoniya [11.8K]

Answer:

x = 1/2

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

$(x+1)^2+(x-1)^2-2x(x+2)=0$
$x^2 + 2x + 1 + x^2 - 2x + 1 -2x^2 -4x = 0$
$(x^2 + x^2-2x^2) + (2x-2x-4x)+(1+1)=0$
$-4x + 2 = 0$

Step 2: Subtract 2 from both sides.

$-4x + 2 - 2 = 0 - 2$
$-4x = -2$

Step 3: Divide both sides by -4.

$\frac{-4x}{-4} = \frac{-2}{-4}$
$x = \frac{1}{2}$

8 0

2 years ago

Help I'll give brainiest.

Tcecarenko [31]

Answer:

See missing answers bold

$20 original = $5 final paid as $15 was s/p before -10 was added

$30 original = $14 final price as $24 was s/p before -10 was added

$60 original = $35 final price as $45 was s/p before -10 was added

$92 original = $69 final price as $59 was s/p before -10 was added

Step-by-step explanation:

Ans in bold

A) = f(x) = 20(0.75) -10 = 15 - 10 = $5 = £5 final paid

B)= f(x) 30 (0.75) = 24 - 10 = 14 = $30 original price

C) = f(x) = 60(0.75) -10 = 45 -10 = $35 = $35 final price

D) = f(x) = 92 (75) = 69 -10 = $59 = $92 original price

8 0

2 years ago

Think about a number line. The integer 3 is 3 units from 0 on the number line. Which integer is also 3 units from 0 on the numbe

disa [49]

-3 is also three units from zero

4 0

2 years ago