Hey there!
Point D is located at point (5, -2)
In coordinates, the first number represents the x-coordinate, and the second number represents the y-coordinate. (TIP: YOU MUST START AT THE ORIGIN, OR (0, 0). In the x-coordinate, you go left/right that number of spaces, left for negative and right for positive. For the y-coordinate, you go up/down that number of spaces, down for negative and up for positive. This means that the point (5, -2) is 5 units right and 2 units down, which lands on point D.
Hope it helps and have an amazing day!
Answer:

Step-by-step explanation:
In order to solve this problem we must start by graphing the given function and finding the differential area we will use to set our integral up. (See attached picture).
The formula we will use for this problem is the following:

where:


a=0

so the volume becomes:

This can be simplified to:

and the integral can be rewritten like this:

which is a standard integral so we solve it to:
![V=9\pi[tan y]\limits^\frac{\pi}{3}_0](https://tex.z-dn.net/?f=V%3D9%5Cpi%5Btan%20y%5D%5Climits%5E%5Cfrac%7B%5Cpi%7D%7B3%7D_0)
so we get:
![V=9\pi[tan \frac{\pi}{3} - tan 0]](https://tex.z-dn.net/?f=V%3D9%5Cpi%5Btan%20%5Cfrac%7B%5Cpi%7D%7B3%7D%20-%20tan%200%5D)
which yields:
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