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zhuklara [117]
3 years ago
8

1 Suppose you choose at random a real number X from the interval [2, 10]. (a) Find the density function f(x) and the probability

of an event E for this experiment, where E is a subinterval [a, b] of [2, 10]. (b) From (a), find the probability that X > 5, that 5 < X < 7, and that X2 − 12X + 35 > 0.
Mathematics
1 answer:
antoniya [11.8K]3 years ago
4 0

Answer:

Step-by-step explanation:

Given that you choose at random a real number X from the interval [2, 10].

a) Since this is a contnuous interval with all number in between equally likely

E = probability for choosing a real number is U(2,10)

pdf of E is \frac{1}{8}

b) P(X>5) = \int\limits^10_5 {1/8} \, dx = \frac{5}{8}

P(5

For

x^2-12x+35 >0\\(x-5)(x-7)>0\\x7

P(X<5 or x>7) = 1-P(5<x<7)

= \frac{3}{4}

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Step-by-step explanation:

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A meteorologist reports that there is a 30% chance the temperature will fall below freezing tomorrow. On any given day, the bus
sladkih [1.3K]
<h3>Answer:  18%</h3>

===========================================================

Explanation:

Convert each percentage to decimal form

  • 30% converts to 0.30
  • 60% converts to 0.60

Then multiply the decimal values

0.30*0.60 = 0.18

That converts to 18%

So there's an 18% chance that both events happen at the same time. In other words, there's an 18% chance of the temperature falling below zero and the bus being late.

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Logan is a land surveyor. He wants to determine d, the distance across a lake that cannot be directly measured. He draws this di
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Answer:

The first option     (5.7km)

Step-by-step explanation:

Since we have a right angle triangle and we know two of its sides we can easily find out the thirds side (the value of d) by using the Pathagoras Theorem. In our case 7 and d are our legs and the hypotenuse is equal to 9, so...

(Based on the Pathagoras Theorem)

c^{2} = a^{2}  + b^{2}

9^{2} = 7^{2} + d^{2}

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A sample survey is designed to estimate the proportion of sports utility vehicles being driven in the state of California. A ran
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Answer:

a) The 95% confidence interval would be given (0.070;0.121).

b) "increase the sample size n"

"decrease za/2 by decreasing the confidence"

Step-by-step explanation:

Notation and definitions

X=48 number of vehicles classified as sports utility.

n=500 random sample taken

\hat p=\frac{48}{500}=0.096 estimated proportion of vehicles classified as sports utility vehicles.

p true population proportion of vehicles classified as sports utility vehicles.

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

(a) Use a 95% confidence interval to estimate the proportion of sports utility vehicles in California. (Round your answers to three decimal places.)

The confidence interval would be given by this formula :

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.5=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

And replacing into the confidence interval formula we got:

0.096 - 1.96 \sqrt{\frac{0.096(1-0.096)}{500}}=0.070

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We are confident (95%) that about 7.0% to 12.1% of vehicles in California are classified as sports utility .  

(b) How can you estimate the proportion of sports utility vehicles in California with a higher degree of accuracy? (HINT: There are two answers. Select all that apply.)

For this case we just have two ways to increase the accuracy one is "increase the sample size n" since if we have a larger sample size the estimation would be more accurate. And the other possibility is "decrease za/2 by decreasing the confidence" because if we decrease the confidence level the interval would be narrower and accurate

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