All categories

3 years ago

NEED HELP PLEASE AND THANKS!

Mathematics

1 answer:

marta [7]3 years ago

5 0

Answer:

The answer is A.

You might be interested in

if 15.9 of every 100 pregnant women in Georgia deliver their babies by c section how many pregnant women out of 25,250 would be

quester [9]

15.9 / 100 = c / 25,250....15.9 c sections to 100 women = c to 25,250 women
cross multiply
(100)(c) = (15.9)(25,250)
100c = 401475
c = 401475/100
c = 4014.75 <===

5 0

3 years ago

Please help me asap!!!

Advocard [28]

Answer:

g=64.8 meters

Step-by-step explanation:

$\frac{26.1}{24.3}$ = $\frac{69.6}{g}$

69.6×24.3= 26.1×g

1,691.28=26.1g

64.8=g

g=64.8

Hope this helps! :)

Oh, I got the order of the ratios wrong, I'm sorry.

I just corrected it.

6 0

3 years ago

Read 2 more answers

Convert:<br> 2 miles 500 feet

Fed [463]

I think you want to convert it all to feet.

1 mile = 5,280 feet

2 miles = 5,280 × 2

5,280 × 2 = 10,560 feet

10,560 + 500 = 11,060 feet

2 miles and 500 feet is equal to 11,060 feet

8 0

3 years ago

Answer plz. Give an explanation so I know ur not just getting points so I dont report. Thank you!

Radda [10]

Answer:

Deji

Step-by-step explanation:

Muhamam

3 0

3 years ago

The numerical course grades in a statistics course can be approximated by a normal model with a mean of 70 and a standard deviat

Naily [24]

Answer:

A = 82.82

B = 72.53

C = 61.58

D = 53.55

Step-by-step explanation:

First, determine the percentile at which the cutoff grade in each letter grade interval falls on and find the equivalent z-score:

A: (100-10) = 90-th percentile

z-score = 1.282

B: (100-10-30) = 60-th percentile

z-score = 0.253

C : (100-10-30-40) = 20-th percentile

z-score = -0.842

D: (100-10-30-40-15) = 5-th percentile

z-score = −1.645

The value 'X' for each cutoff can be found by applying the z-score equation:

$z= \frac{X- \mu }{SD}$

Where μ is the mean and SD is the standard deviation

Therefore, the cutoffs are:

$1.282= \frac{X(A)- 70}{10}\\X(A) = 10*1.282 +70\\X(A) = 82.82\\\\0.253 = \frac{X(B)- 70}{10}\\X(B) = 10*0.253 +70\\X(B) = 72.53\\\\0.253 = \frac{X(C)- 70}{10}\\X(C) = 10*-0.842 +70\\X(C) = 61.58\\\\0.253 = \frac{X(D)- 70}{10}\\X(D) = 10*-1.645 +70\\X(D) = 53.55\\$

6 0

3 years ago