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sergij07 [2.7K]

3 years ago

9

A certain mail service charges $15 for an overnight package, plus 18 cents per pound. Find the cost of mailing a 40-pound packag

e through this company.

1 answer:

Ksivusya [100]3 years ago

5 0

Cost = $15 + $ .18x

y = .18 (40) + 15
y = 7.2 + 15
y = 22.2

so the answer is $22.20

check:

22.20 = .18x + 15
7.2 = .18x
x = 40

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amm1812

X/6 + 4 = 15

First, subtract 4 to both sides:

x/6 = 11

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4 0

3 years ago

Read 2 more answers

Nina delivers newspapers. In the first week, she delivers 8 papers. In the second week, she delivers 32 papers. Which equation c

Romashka-Z-Leto [24]

Answer:

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b) Nina delivered 4 times as many papers the second week as the first week

Step-by-step explanation:

From the question, we are told that:

Nina delivers newspapers.

In the first week, she delivers 8 papers.

In the second week, she delivers 32 papers.

Let x represent the number of times

The equation can Nina use to find how many times as many papers she delivered the second week as the first week is given as:

8paper × x = 32 papers

8x = 32

Solving for x

8x = 32

x = 32/8

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Therefore, Nina delivered 4 times as many papers the second week as the first week

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2 years ago

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6 0

1 year ago

6-2x=y 14+3x=y plzzz helllllllllllllllp

pashok25 [27]

Answer:

(- $\frac{8}{5}$ , $\frac{46}{5}$ )

Step-by-step explanation:

Given the2 equations

6 - 2x = y → (1)

14 + 3x = y → (2)

Substitute y = 14 + 3x into (1)

6 - 2x = 14 + 3x ( subtract 3x from both sides )

6 - 5x = 14 ( subtract 6 from both sides )

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x = - $\frac{8}{5}$

Substitute x = - $\frac{8}{5}$ into either of the 2 equations for the corresponding value of y

Substituting into (1)

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8 0

2 years ago

Identify the quotient in the form a + bi. HELP ASAP PLEASE!!

Step2247 [10]

Solving the expression $\frac{4-5i}{2+3i}$ we get $-\frac{7}{13}-\frac{22i}{13}$

So, Option A is correct.

Step-by-step explanation:

We need to solve the expression: $\frac{4-5i}{2+3i}$

Multiplying and dividing by 2-3i

$=\frac{4-5i}{2+3i}*\frac{2-3i}{2-3i}\\=\frac{4-5i*2-3i}{2+3i*2-3i}\\=\frac{4(2-3i)-5i(2-3i)}{(2)^2-(3i)^2}\\=\frac{8-12i-10i+15i^2)}{4-9i^2}\\We\,\,know\,\, i^2=-1\\=\frac{8-12i-10i+15(-1)}{4-9(-1)}\\=\frac{8-15-12i-10i}{4+9}\\=\frac{-7-22i}{13}\\=-\frac{7}{13}-\frac{22i}{13}$

So, solving the expression $\frac{4-5i}{2+3i}$ we get $-\frac{7}{13}-\frac{22i}{13}$

So, Option A is correct.

Keywords: Complex numbers

Learn more about Complex numbers at:

#learnwithBrainly

8 0

3 years ago