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Anni [7]
3 years ago
5

Select the three ratios that represent the number of blue marbles to red marbles.

Mathematics
2 answers:
wlad13 [49]3 years ago
8 0

Answer: Either 2:3 or 3:2

just olya [345]3 years ago
6 0
6:9, if you need more just simply find common ratios or simplify.
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Please help. I will give Brainliest! I pinky promise! Please refer to all 3 pictures attached!
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Step-by-step explanation:

B. the vertex is (-6,-2)

C. 1

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2 years ago
What type of triangle has 3 sides that are the same length?
koban [17]
An equilateral triangle.
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When a depependent variable increases and the independent variable increases what is the constant rate of Change
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3 years ago
Due to a manufacturing error, two cans of regular soda were accidentally filled with diet soda and placed into a 18-pack. Suppos
crimeas [40]

Answer:

a) There is a 1.21% probability that both contain diet soda.

b) There is a 79.21% probability that both contain diet soda.

c)  P(X = 2) is unusual, P(X = 0) is not unusual

d) There is a 19.58% probability that exactly one is diet and exactly one is regular.

Step-by-step explanation:

There are only two possible outcomes. Either the can has diet soda, or it hasn't. So we use the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

A number of sucesses x is considered unusually low if P(X \leq x) \leq 0.05 and unusually high if P(X \geq x) \geq 0.05

In this problem, we have that:

Two cans are randomly chosen, so n = 2

Two out of 18 cans are filled with diet coke, so \pi = \frac{2}{18} = 0.11

a) Determine the probability that both contain diet soda. P(both diet soda)

That is P(X = 2).

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 2) = C_{2,2}(0.11)^{2}(0.89)^{0} = 0.0121

There is a 1.21% probability that both contain diet soda.

b)Determine the probability that both contain regular soda. P(both regular)

That is P(X = 0).

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 0) = C_{2,0}(0.11)^{0}(0.89)^{2} = 0.7921

There is a 79.21% probability that both contain diet soda.

c) Would this be unusual?

We have that P(X = 2) is unusual, since P(X \geq 2) = P(X = 2) = 0.0121 \leq 0.05

For P(X = 0), it is not unusually high nor unusually low.

d) Determine the probability that exactly one is diet and exactly one is regular. P(one diet and one regular)

That is P(X = 1).

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 1) = C_{2,1}(0.11)^{1}(0.89)^{1} = 0.1958

There is a 19.58% probability that exactly one is diet and exactly one is regular.

8 0
3 years ago
F(x) = x + 4<br> G(x) = x^2 + 4<br> Find (fog) (3)
Anika [276]
Answer: 17

Steps:

1. Plug in (3) into “x” of the g(x) equation:
g(3) = (3)^2 + 4
g(3) = 9 +4
g(3) = 13

2. Plug in g(3) value into “x” of the f(x) equation:
f(g(3)) = x + 4
f(g(3)) = 13 + 4
f(g(3)) = 17
5 0
3 years ago
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