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Sonbull [250]
3 years ago
9

How can I use benchmarks to estimate 9/10+4/10

Mathematics
1 answer:
Jobisdone [24]3 years ago
4 0
I don’t kno how to estimate using benchmarks but I kno the exacts answer is 13/10 or 1.3
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For which distributions is the median the best measure of center?
frutty [35]

Answer:

2

Step-by-step explanation:

6 0
3 years ago
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2. The Welcher Adult Intelligence Test Scale is composed of a number of subtests. On one subtest, the raw scores have a mean of
IgorC [24]

Answer:

a) 37.31 b) 42.70 c) 0.57 d) 0.09

Step-by-step explaanation:

We are regarding a normal distribution with a mean of 35 and a standard deviation of 6, i.e., \mu = 35 and \sigma = 6. We know that the probability density function for a normal distribution with a mean of \mu and a standard deviation of \sigma is given by

f(x) = \frac{1}{\sqrt{2\pi}\sigma}\exp[-\frac{(x-\mu)^{2}}{2\sigma^{2}}]

in this case we have

f(x) = \frac{1}{\sqrt{2\pi}6}\exp[-\frac{(x-35)^{2}}{2(6^{2})}]

Let X be the random variable that represents a row score, we find the values we are seeking in the following way

a)  we are looking for a number x_{0} such that

P(X\leq x_{0}) = \int\limits^{x_{0}}_{-\infty} {f(x)} \, dx = 0.65, this number is x_{0}=37.31

you can find this answer using the R statistical programming languange and the instruction qnorm(0.65, mean = 35, sd = 6)

b) we are looking for a number  x_{1} such that

P(X\leq x_{1}) = \int\limits^{x_{1}}_{-\infty} {f(x)} \, dx = 0.9, this number is x_{1}=42.70

you can find this answer using the R statistical programming languange and the instruction qnorm(0.9, mean = 35, sd = 6)

c) we find this probability as

P(28\leq X\leq 38)=\int\limits^{38}_{28} {f(x)} \, dx = 0.57

you can find this answer using the R statistical programming languange and the instruction pnorm(38, mean = 35, sd = 6) -pnorm(28, mean = 35, sd = 6)

d) we find this probability as

P(41\leq X\leq 44)=\int\limits^{44}_{41} {f(x)} \, dx = 0.09

you can find this answer using the R statistical programming languange and the instruction pnorm(44, mean = 35, sd = 6) -pnorm(41, mean = 35, sd = 6)

6 0
3 years ago
Read 2 more answers
5000 rounded to the nearest 10 thousand
Serga [27]
It only thousand you can't rounded to ten thousand
6 0
3 years ago
Henri has $24000 invested in stocks and bonds. The amount in stocks is $6000 more than three times the amount in bonds. Call the
andrey2020 [161]

Answer:

Henri invested $ 4,500 in bonds and $ 19,500 in stocks.

Step-by-step explanation:

Given that Henri has $ 24000 invested in stocks and bonds, and the amount in stocks is $ 6000 more than three times the amount in bonds, to determine the amount that Henri invested in stocks (S) and the amount he invested in bonds (B), the following calculations must be performed:

6000 + 3B + B = 24000

3B + B = 24000 - 6000

4B = 18000

B = 18000/4

B = 4500

S = 6000 + 3x4500

S = 6000 + 13500

S = 19500

Thus, Henri invested $ 4,500 in bonds and $ 19,500 in stocks.

7 0
3 years ago
Two friends, Alejandro and Mia, agreed to split the check at a restaurant. Alejandro ordered $12 worth of food and Mia ordered $
kvasek [131]

Cost of Alejandro's food = $12

Tip paid by Alejandro = 20% of his bill = 20% of 12 = 2.4

Cost of Mia's food = $18

Tip paid by Mia = 15% of his bill = 15% of 18 = 2.7

Total Tip Paid = 2.4+2.7 = 5.1

Total Check Amount = 12 + 18 = 30

Total tip paid by Alejandro and Mia is r% of the total check amount.

So, we need to determine what % of 30 is equal to 5.1%

⇒ r% × 30 = 5.1

⇒ r% = 5.1 / 30

⇒ r% = 17%

Hence, r is 17%

8 0
3 years ago
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