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3 years ago

which point could be removed in order to make it the relation a function? (-4, 3) (-5, 6) (1, 0) (-4, 5) (9, 5) (0, -7)

2 answers:

6 0

In a function, each input (x-) value has exactly one output (y-) value. That's not the case here, where we have (-4,5) and (-4,3) (two different y-values for one x-value). Eliminating either (-4,5) or (-4,3) will make this relation into a function.

Studentka2010 [4]3 years ago

5 0

(-4, 5)

Because the -4 for x was used already

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What is the solution to the equation 3/m+3-m/3-m=m^2+9/m^2-9

Bas_tet [7]

Answer:

no solution

Step-by-step explanation:

If we subtract the left side of the equation, we get ...

$\dfrac{m^2+9}{m^2-9}-\dfrac{3}{m+3}+\dfrac{3}{3-m}=0\\\\\dfrac{m^2+9-3(m-3)-3(m+3)}{(m-3)(m+3)}=0\\\\\dfrac{m^2-6m+9}{(m-3)(m+3)}=0=\dfrac{(m-3)^2}{(m-3)(m+3)}\\\\\dfrac{m-3}{m+3}=0\quad\text{m$\ne$3}$

This equation will equal zero only if m=3, which is disallowed because it makes the denominator zero. Thus, there is no solution.

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3 years ago

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riadik2000 [5.3K]

Answer:

31/8

Step-by-step explanation:

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2 years ago

Uh Expanded form pls? 4.02 x 10^5

Vera_Pavlovna [14]

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Step-by-step explanation:

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4.02 x 10 x 10 x 10 x 10 x 10

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3 years ago

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Write a quadratic function in vertex form whose graph has the vertex (1, 0) and passes through the point (2, −17).

Brilliant_brown [7]

Answer:

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Step-by-step explanation:

6 0

3 years ago

Emil is running a lemonade stand. He sells half of his lemonade in the morning, a quarter of what was left at lunchtime, and a t

masya89 [10]

Emil starts the day with <u>16 liters</u> of lemonade if he is left with 4 liters by the end of the day. Computed using the fractional values given.

Let the initial quantity of lemonade with Emil be x liters.

Quantity sold by Emil in the morning = Half of his lemonade = (1/2)x liters, that is half fraction of x.

Quantity left with Emil = x - x/2 = x/2 liters, that is half fraction of x.

Quantity sold by Emil at lunchtime = Quarter of what was left = (1/4)(x/2) liters = x/8 liters, that is the one-eight fraction of x.

Quantity left with Emil = x/2 - x/8 = 3x/8 liters, that is the three-eight fraction of x.

Quantity sold by Emil in the afternoon = One-third of what was left = (1/3)(3x/8) liters = x/8 liters, that is the one-eight fraction of x.

Quantity left with Emil = 3x/8 - x/8 = x/4 liters, that is the quarter fraction of x.

Now, we are said that Emil closes for the day with 4 liters remaining.

Therefore, x/4 = 4, or, x = 4*4 = 16 liters.

Therefore, Emil started the day with 16 liters of lemonade.

Learn more about fractions at

brainly.com/question/11562149

#SPJ10

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1 year ago