Question

The square of the sum of 7 times x and 3 divided by 4 times the difference of c and 1

Answer 1

The second answer from the top is correct. Your original choice is incorrect because the 7x and the 3 are not both being squared as the statement suggests.

Answer 2

Answer:

$\frac{(7x+3)^2}{4(x-1)}$

Step-by-step explanation:

The square of the sum of 7 times x and 3 divided by 4 times the difference of x and 1

Convert the verbal statement into an expression

sum of 7 times x  and 3 become 7x+3, for sum we add

for square we put exponent 2, square of the sum (7x+3) becomes (7x+3)^2

differeence of x and 1 is x-1

4 times the difference means we multiply by 4

it becomes 4(x-1)

The square of the sum of 7 times x and 3 divided by 4 times the difference of x and 1

(7x+2)^2 divide by 4(x-1)

$\frac{(7x+3)^2}{4(x-1)}$