Answer:
The work done to pump all of the kerosene from the tank to an outlet is 
Step-by-step explanation:
The work is defined by:
(1)
The force here will be the product between the volume and the kerosene weighing, so we have :
This force will be in-lbs.
Where R is the radius (3 feet)
Then using (1), we have:
Here 8-y is a distance at some point of the tank. Now, to get the work done from the base to the top of the tank we will need to take integral from 0 to 8 feet.
Therefore, the work done to pump all of the kerosene from the tank to an outlet is
I hope it helps you!
Answer:
-30 m
Step-by-step explanation:
lmk if its right
Answer:
C. $97
Step-by-step explanation:
The average of his wage for all 15 days is the sum of all wages for the 15 days divided by 15.
average wage for 15 days = (sum of wages for the 15 days)/15
The amount of wages during a number of days is the product of the average wage of those days and the number of days.
First 7 days:
average wage: $87
number of days: 7
total wages in first 7 days = 7 * $87/day = $609
Last 7 days:
average wage: $92
number of days: 7
total wages in last 7 days = 7 * $92/day = $644
8th day:
wages of the 8th day is unknown, so we let x = wages of the 8th day
total wages of 15 days = (wages of first 7 days) + (wages of 8th day) + (wages of last 7 days)
total wages of 15 days = 609 + x + 644 = x + 1253
average wage for 15 days = (sum of wages for the 15 days)/15
average wage for 15 days = (x + 1253)/15
We are told the average for the 15 days is $90/day.
(x + 1253)/15 = 90
Multiply both sides by 15.
x + 1253 = 1350
Subtract 1253 from both sides.
x = 97
Answer: $97
Answer:77 and 87
Step-by-step explanation:
7×6=42 + 5+7=35/\ 35+42=77(first outcome)
7×6=42 + 5×9=45/\42+45=87 (second outcome.
Answer: A: 3x^2y^(3/2)
Step-by-step explanation:
This can be written as
(81*x^8*y^6)^(1/4)
Then multiply each exponent by (1/4):
81^(1/4)*x^(8(1/4))y^6(1/4))
81^(1/4) = 3
x^(8(1/4)) = x^2
y^6(1/4)) = y^(3/2)
The result: 3x^2y^(3/2)
