Question

PRECALCULUS please help​

Answer 1

Answer:

$( f - g)(x) = \frac{2x - \sqrt{x} + 14 }{3x}$

Step-by-step explanation:

$f(x) = \frac{2x + 6}{3x} \\ \\ g(x) = \frac{ \sqrt{x} - 8}{3x}$

To find ( f - g)(x) , subtract g(x) from f(x)

That's

$( f - g)(x) = \frac{2x + 6}{3x} - \frac{ \sqrt{x} - 8}{3x}$

Since they have a common denominator that's 3x we can subtract them directly

That's

$\frac{2x + 6}{3x} - \frac{ \sqrt{x} - 8}{3x} = \frac{2x + 6 - ( \sqrt{x} - 8) }{3x} \\ = \frac{2x + 6 - \sqrt{x} + 8 }{3x} \\ = \frac{2x - \sqrt{x} + 6 + 8 }{3x}$

We have the final answer as

$( f - g)(x) = \frac{2x - \sqrt{x} + 14 }{3x}$

Hope this helps you