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3 years ago

7

PRECALCULUS please help

1 answer:

sergejj [24]3 years ago

6 0

Answer:

<h2> $( f - g)(x) = \frac{2x - \sqrt{x} + 14 }{3x}$ </h2>

Step-by-step explanation:

$f(x) = \frac{2x + 6}{3x} \\ \\ g(x) = \frac{ \sqrt{x} - 8}{3x}$

To find ( f - g)(x) , subtract g(x) from f(x)

That's

$( f - g)(x) = \frac{2x + 6}{3x} - \frac{ \sqrt{x} - 8}{3x}$

Since they have a common denominator that's 3x we can subtract them directly

That's

$\frac{2x + 6}{3x} - \frac{ \sqrt{x} - 8}{3x} = \frac{2x + 6 - ( \sqrt{x} - 8) }{3x} \\ = \frac{2x + 6 - \sqrt{x} + 8 }{3x} \\ = \frac{2x - \sqrt{x} + 6 + 8 }{3x}$

We have the final answer as

<h3> $( f - g)(x) = \frac{2x - \sqrt{x} + 14 }{3x}$ </h3>

Hope this helps you

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2 years ago

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Answer:

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Step-by-step explanation:

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For this problem, we have that:

Based on the study results, we can assume the population mean and standard deviation for the GPA of nontraditional students is $\mu = 3.5$ and $\sigma = 0.5$ .

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2 years ago

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2 years ago