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qaws [65]
4 years ago
13

Someone help me and remember to show your work so I know how to do it!

Mathematics
1 answer:
Monica [59]4 years ago
6 0
(x^15)(x^-3) = x^(15 + (-3)) = x^12
n = 12
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Pls help Question On the photo
Mrac [35]

Answer:

C. In step 2, Cindy should have multiplied both sides of the equation by 2.

Step-by-step explanation:

I'll go through the equation correctly, and then point out what would have happened.

3 = x/2 - 5

Add 5 to both sides. -5 and 5 cancel out.

8 = x/2

What Cindy should have done here is multiply by 2, not divide by 2. It is important to remember that you do the INVERSE operation to cancel out a number.

What would have happened here is that we have an extra step (though either way we still end up with x being 16.)

Correct Step 2:

Multiply both sides by 2. x/2 and 2x cancel out.

x = 16

Incorrect Step 2:

8/2 = (x/2)/2

4 = x/4

Multiply both sides by 4 (this would be the extra step!).

16 = x

8 0
3 years ago
find the height of a cylinder whose volume is 41.5 cubic yards and has a radius of 2 yards. Please help
chubhunter [2.5K]
General formula :
V = pi x radius squared x height 
 
41.5 = pi x 4 x h 
41.5 = 4pi x h 
41.5/4pi = h 
3.302465069 = h 

4 0
3 years ago
Which of the following can be used to support the idea that the set of polynomials is closed under multiplication?
bekas [8.4K]

Answer

Step-by-step explanation:

7 0
2 years ago
A rectangular field is
mojhsa [17]
350x300=105000m squared
1km=1000m
So, 105000=105km squared
8 0
3 years ago
Read 2 more answers
Solve the compound inequality<br> 3t-8/5 and 4-t&lt;-7
Sav [38]

Answer: -2.8

Step-by-step explanation:

3t-(8/5) * 4-t < -7

(15t-8)/5 * 4-t < -7

((15t-8)(4-t))/5 < -7

(15t^2)-28t-32< -7

(15t^2)-28t-32-7< 0

(15t^2)-28t-39< 0

Using the quadratic/almighty formula

t= (-b +- ((b^2)-4ac)^(1/2)/2a)

a=15, b=-28, c=-39

t= (-(28) +- (((-28)^2)-4(15)(-39))^(1/2))/2(15))

t= -2.8 or t= 0.9

Since

t<0, then t= -2.8

8 0
3 years ago
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