1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
qaws [65]
3 years ago
13

Someone help me and remember to show your work so I know how to do it!

Mathematics
1 answer:
Monica [59]3 years ago
6 0
(x^15)(x^-3) = x^(15 + (-3)) = x^12
n = 12
You might be interested in
Using the equation Y= 2/3x - 5 describe how to create a system of linear equations with an infinite number of solutions.
just olya [345]
If you think about this equation as a line, then in order to have an infinite number of solutions is to have another equation that describes the same line.

So, for example 3y=2x-15 would be one of those.
3 0
3 years ago
Read 2 more answers
Cleo added 3a+4b and got 7ab. Three of these statements explain why her answer is wrong. Which one does not
Triss [41]

Answer:

3 and 4 are factors of 12 so they should be multiplied to get a product of 12 ab. (Answer D)

Step-by-step explanation:

You do not multiply in addition unless an exponent is present. You should not multiply or add considering these are not like terms. Therefore, D is wrong.

5 0
3 years ago
What are the vertex focus and directrix of a parabola with equation x=y^2+14y-2
zimovet [89]
This is a sideways opening parabola, opening to the right to be more specific, since the leading coefficient is a positive 1.  The rule for a focus and a directrix is that they are the same number of units from the vertex (in other words, the vertex is dead center between them), and that the vertex is on the same axis that the focus is.  We need to find the vertex then to determine what the focus and the directrix are.  We will complete the square on that to find the vertex.  Begin by setting it equal to 0, then move the 2 over by addition to get y^2+14y=2.  Now we will complete the square on the y terms.  Take half the linear term, square it, and add it to both sides.  Our linear term is 14.  Half of 14 is 7, and 7 squared is 49. So we add 49 to both sides. y^2+14y+49=2+49, which of course simplifies to y^2+14y+49=51.  The purpose of this is to find the k coodinate of the vertex which will be revealed when we write the perfect square binomial we created during this process: (y+7)^2=51.  Moving the 51 back over by subtraction gives us (y+7)^2-51=x.  The vertex then is (-51,-7).  The formula to find the focus using this vertex is (h+ \frac{1}{4a},k).  As I stated quite a while ago, the leading coefficient on our parabola was a +1 so our "a" value is 1, and the focus is then found in (-51+ \frac{1}{4},-7) which simplifies to (-50.75, -7).  If the vertex is (-51, -7) and the focus is (-50.75, -7), then the distance between them is 1/4, or .25.  That means that the directrix is also .25 units from the vertex, but in the other direction.  Our directrix is a vertical line, and it will have the equaion x = -51.25.  Summing up, your focus is (-50.75, -7) and your directrix is x = -51.25
7 0
3 years ago
Ajar contains 4 red marbles numbered 1 to 4 and 10 blue marbles numbered 1 to 10. A marble is
Reptile [31]

Answer:

a)2/7

b)1/2

c)9/14

d)6/7

Step-by-step explanation:

The jar contains 4 red marbles, numbered 1 to 4 which means

Red marbles = (R1) , (R2) , (R3) , (R4)

It also contains 10 blue marbles numbered 1 to 10 which means

Blue marbles = (B1) , (B2) , (B3) , (B4) , (B5) , (B6) , (B7) , (B8) , (B9) , (B10) .

We can calculate total marbles = 4red +10 blues

=14marbled

Therefore, total marbles= 14

The marbles that has even number = (R2) , (R4) ,(B2) , (B4) , (B6) , (B8) , (B10) =7

Total number of Blue marbles = 10

Blue and even marbles = 5

(a) The marble is red

P(The marble is red)=total number of red marbles/Total number of marbles

=4/14

=2/7

(b) The marble is odd-numbered

Blue marbles with odd number= (B1) , (B3) , (B5) , (B7) , (B9) ,

Red marbles with odd number = (R1) , (R3)

Number of odd numbered =(5+2)=7

P(marble is odd-numbered )= Number of odd numbered/ Total number of marbles

P(marble is odd-numbered )=7/14

=1/2

(C) The marble is red or odd-numbered?

Total number of red marbles = 14

Number of red and odd marbles = 2

The marbles that has odd number = (R1) , (R3) ,(B1) , (B3) , (B5) , (B7) , (B9) =7

n(red or even )= n(red) + n(odd)- n(red and odd)

=4+7-2

=9

P(red or odd numbered)= (number of red or odd)/(total number of the marble)

= 9/14

(d) The marble is blue or even-numbered?

Number of Blue and even marbles = 5

Total number of Blue marbles = 10

Number of blue that are even= 5

The marbles that has even number = (R2) , (R4) ,(B2) , (B4) , (B6) , (B8) , (B10)

=7

n(Blue or even )= n(Blue) + n(even)- n(Blue and even)

= 10+7-5 =12

Now , the probability the marble is blue or even numbered can be calculated as

P(blue or even numbered)= (number of Blue or even)/(total number of the marble)

= 12/14

= 6/7

6 0
2 years ago
(percentages aren't my forte) 91% of what is 108?
Pavel [41]

Answer:

98.28

Step-by-step explanation:

its kinda easy

8 0
3 years ago
Read 2 more answers
Other questions:
  • How do I find the slant height of a square pyramid? The base length is 4 inches and the area of it is 136 square inches. Thank y
    6·1 answer
  • Perform the indicated operation -100/5
    10·2 answers
  • Which number can each term of the equation be multiplied by to eliminate the fractions before solving?
    10·1 answer
  • Find the center, vertices, and foci of the ellipse with equation x squared divided by 36 plus y squared divided by 100 = 1
    10·1 answer
  • Resuelve estas ecuaciones<br> 1. x I 6 = 14<br> X=
    8·1 answer
  • What is the simplified from of pi √3-8 pi√3<br>​
    12·1 answer
  • Are the triangles similar? If so, why?
    9·1 answer
  • Round 81.469 to 1 decimal place.
    8·1 answer
  • HELP WILL GIVE BRAINLIEST SHOW WORK LOOK AT IMAGE
    12·1 answer
  • Bc
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!