Answer:
5375 should be it
Step-by-step explanation:
Answer:
What are we trying to figure out with this information??
P.S. I am not collecting the points, I will revise my answer once you fix the question!! :)
Answer:
7.2 years
Step-by-step explanation:
![f(t) =200(1 - 0.956e^{-0.18t})](https://tex.z-dn.net/?f=f%28t%29%20%3D200%281%20-%200.956e%5E%7B-0.18t%7D%29)
where f(t) is the length and t is the number of years old
given the Mike measures 148 cm, we need to find out the age
So we plug in 148 for f(t) and solve for t
![148 =200(1 - 0.956e^{-0.18t})](https://tex.z-dn.net/?f=148%20%3D200%281%20-%200.956e%5E%7B-0.18t%7D%29)
divide both sides by 200
![\frac{148}{200} = 1 - 0.956e^{-0.18t}](https://tex.z-dn.net/?f=%5Cfrac%7B148%7D%7B200%7D%20%3D%201%20-%200.956e%5E%7B-0.18t%7D)
Now subtract 1 from both sides
![-0.26= - 0.956e^{-0.18t}](https://tex.z-dn.net/?f=-0.26%3D%20-%200.956e%5E%7B-0.18t%7D)
Divide both sides by -0.956
![\frac{0.26}{0.956} =e^{-0.18t}](https://tex.z-dn.net/?f=%5Cfrac%7B0.26%7D%7B0.956%7D%20%3De%5E%7B-0.18t%7D)
Now take ln on both sides
![\frac{0.26}{0.956} =e^{-0.18t}](https://tex.z-dn.net/?f=%5Cfrac%7B0.26%7D%7B0.956%7D%20%3De%5E%7B-0.18t%7D)
![ln(\frac{0.26}{0.956} )=-0.18tln(e)](https://tex.z-dn.net/?f=ln%28%5Cfrac%7B0.26%7D%7B0.956%7D%20%29%3D-0.18tln%28e%29)
![ln(\frac{0.26}{0.956} )=-0.18t](https://tex.z-dn.net/?f=ln%28%5Cfrac%7B0.26%7D%7B0.956%7D%20%29%3D-0.18t)
divide both sides by -0.18
t=7.2
So 7.2 years
The distance between the coordinates (0, 4) and (10,4) is 10
Step-by-step explanation:
We need to find the distance between the coordinates (0, 4) and (10,4)
The formula used to find distance is:
![Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=Distance%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
where
![x_1=0, y_1=4, x_2=10,y_2=4](https://tex.z-dn.net/?f=x_1%3D0%2C%20y_1%3D4%2C%20x_2%3D10%2Cy_2%3D4)
Putting values:
![Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\Distance=\sqrt{(10-0)^2+(4-4)^2}\\Distance=\sqrt{(10)^2+(0)^2}\\Distance=\sqrt{(10)^2}\\Distance=10](https://tex.z-dn.net/?f=Distance%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D%5C%5CDistance%3D%5Csqrt%7B%2810-0%29%5E2%2B%284-4%29%5E2%7D%5C%5CDistance%3D%5Csqrt%7B%2810%29%5E2%2B%280%29%5E2%7D%5C%5CDistance%3D%5Csqrt%7B%2810%29%5E2%7D%5C%5CDistance%3D10)
So, The distance between the coordinates (0, 4) and (10,4) is 10
Keywords: Distance between coordinates
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