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2 years ago

Which name correctly classifies this triangle? A. right B. obtuse C. acute

Mathematics

1 answer:

sergejj [24]2 years ago

7 0

Hello there!

The would be a (right angle) because this angle is not greater than, or less than 90°.

Your correct answer would be the first option. (right angle).

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I can't figure this out and didn't see it on brainly, pls help

ch4aika [34]

Answer:

it's 8

Step-by-step explanation:

(10×1/5)^3=2^3=8

6 0

2 years ago

Read 2 more answers

On Sunday, a local hamburger shop sold a combined total of 378 hamburgers and cheeseburgers. The number of cheeseburgers was sol

ipn [44]

Answer:

The number of hamburgers sold was 126.

Step-by-step explanation:

Let h = number of hamburgers sold

let c = cheeseburgers sold

c+h = 378

c = 2h

Substitute c =2h into c+h =278

c+h =378

2h+h = 378

Combine like terms

3h = 378

Divide by 3

3h/3 =378/3

h =126

The number of hamburgers sold was 126.

5 0

2 years ago

Can someone please help mee

devlian [24]

Answer:

B is (7,-4) C is (7,-2) D is (5,0)

Step-by-step explanation:

Trust me

5 0

2 years ago

10. Two lighthouses are located on a north-south line.

Kamila [148]

The question is an illustration of bearing (i.e. angles) and distance (i.e. lengths)

The distance between both lighthouses is 5783.96 m

I've added an attachment that represents the scenario.

From the attachment, we have:

$\mathbf{\angle A = 180^o - 120^o\ 43'}$

Convert to degrees

$\mathbf{\angle A = 180^o - (120^o +\frac{43}{60}^o)}$

$\mathbf{\angle A = 180^o - (120^o +0.717^o)}$

$\mathbf{\angle A = 180^o - (120.717^o)}$

$\mathbf{\angle A = 59.283^o}$

$\mathbf{\angle B = 39^o43'}$

Convert to degrees

$\mathbf{\angle B = 39^o + \frac{43}{60}^o}$

$\mathbf{\angle B = 39^o + 0.717^o}$

$\mathbf{\angle B = 39.717^o}$

So, the measure of angle S is:

$\mathbf{\angle S = 180 - \angle A - \angle B}$ ---- Sum of angles in a triangle

$\mathbf{\angle S = 180 - 59.283 - 39.717}$

$\mathbf{\angle S = 81}$

The required distance is distance AB

This is calculated using the following sine formula:

$\mathbf{\frac{AB}{\sin(S)} = \frac{AS}{\sin(B)} }$

Where:

$\mathbf{AS = 3742}$

So, we have:

$\mathbf{\frac{AB}{\sin(81)} = \frac{3742}{\sin(39.717)}}$

Make AB the subject

$\mathbf{AB= \frac{3742}{\sin(39.717)} \times \sin(81)}$

$\mathbf{AB= 5783.96}$

Hence, the distance between both lighthouses is 5783.96 m

Read more about bearing and distance at:

brainly.com/question/19017345

5 0

1 year ago

SOMEONE PLEASE TRY AND HELP ME ASAPPPP‼️‼️‼️ WHO’S GOOD AT MATHS⁉️

DanielleElmas [232]

Hmmmm

This looks like homework, you sure you've read the terms of service?

3 0

2 years ago