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bija089 [108]
3 years ago
7

Evaluate the algebraic expression: 7k - 4k when k= 6

Mathematics
1 answer:
agasfer [191]3 years ago
4 0
The answer would be 18. K can be plugged into the equation to become (7*6 - 4*6) which would then become (42-24). This then becomes 18
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Please help me out on this question
Mariulka [41]

At x=2, y=4

At x=4, y=16

So the total change in y from x=2 to x=4 is 16-4=12

And since average rate of change = total change in y divided by total change in x within the same period, therefore the answer is 12/2 = 6

Hope that helps. Let me know if you have any questions.

7 0
3 years ago
The amount of money, in dollars, Sarah has in her savings account is modeled as a function of time in months. This function is r
hjlf

Answer:

330.60.330.60.330.60.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Helppppp. Pleaseee? :(
mylen [45]
There isnt enough information to solve the question, answer is E.
5 0
3 years ago
Read 2 more answers
Let X denote the data transfer time (ms) in a grid computing system (the time required for data transfer) between a "worker" com
My name is Ann [436]

Answer:

a. The value of alpha is 3.014 and the value of beta is 12.442

b. The probability that data transfer time exceeds 50ms is 0.238

c. The probability that data transfer time is between 50 and 75 ms is 0.176

Step-by-step explanation:

a. According to the given data we have that the mean and standard deviation of the random variable X are 37.5 ms and 21.6.

Therefore, E(X)=37.5 and V(X)=(21.6)∧2  

To calculate alpha we would have to use the following formula:

alpha=E(X)∧2/V(X)

alpha=(37.5)∧2/21.6∧2

alpha=1,406.25 /466.56

​alpha=3.014

To calculate beta we would have to use the following formula:

β=  V(X) ∧2/E(X)

β=(21.6)  ∧2/37.5

β=466.56 /37.5

β=12.442

b. E(X)=37.5 and V(X)=(21.6)∧2  

Therefore, P(X>50)=1−P(X≤50)

Hence, To calculate the probability that data transfer time exceeds 50ms we use the following formula:

P(X>50)=1−P(X≤50)

=1−0.762

=0.238

The probability that data transfer time exceeds 50ms is 0.238

c. E(X)=37.5 and V(X)=(21.6)∧2  

​Therefore, P(50<X<75)=P(X<75)−P(X<50)  

Hence, To calculate the probability that data transfer time is between 50 and 75 ms we use the following formula:

P(50<X<75)=P(X<75)−P(X<50)

=0.938−0.762

=0.176

​

The probability that data transfer time is between 50 and 75 ms is 0.176

6 0
3 years ago
How do I solve this I'm having a problem.
Llana [10]
How do you solve what
4 0
3 years ago
Read 2 more answers
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