Question

Write a program that prints all the numbers from 0 to 6 except 3 and 6. Expected output: 0 1 2 4 5

Answer 1

Answer:

for x in range(7):

   if (x == 3 or x==6):

       continue

   print(x, end=' ')

print("\n")

Output:

>> 0 1 2 4 5

Explanation:

The code above has been written in Python. The following explains each line of the code.

Line 1: for x in range(7):

The built-in function range(7)  generates integers between 0 and 7. 0 is included but not 7. i.e 0 - 6.

The for loop then iterates over the sequence of number being generated by the range() function. At each iteration, the value of x equals the number at that iteration. i.e

For the first iteration, x = 0

For the second iteration, x = 1

For the third iteration, x = 2 and so on up to x = 6 (since the last number, 7, is not included).

Line 2: if (x == 3 or x == 6):

This line checks for the value of x at each iteration. if the value of x is 3 or 6, then the next line, line 3 is executed.

Line 3: continue

The continue keyword is used to skip an iteration in a loop. In other words, when the continue statement is encountered in a loop, the loop skips to the next iteration without executing expressions that follow the continue statement in that iteration. In this case, the print(x, end=' ')  in line 4 will not be executed when x is 3 or 6. That means 3 and 6 will not be printed.

Line 4: print(x, end=' ')

This line prints the value of x at each iteration(loop) and then followed by a single space. i.e 0 1 2 ... will be printed. Bear in mind that 3 and 6 will not be printed though.

Line 5: print("\n")

This line will be printed after the loop has finished execution. This line prints a new line character.