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3 years ago

Write a program that prints all the numbers from 0 to 6 except 3 and 6. Expected output: 0 1 2 4 5

Computers and Technology

1 answer:

stellarik [79]3 years ago

8 0

<h2>Answer:</h2><h2></h2>

for x in range(7):

if (x == 3 or x==6):

continue

print(x, end=' ')

print("\n")

<h2>Output:</h2>

>> 0 1 2 4 5

<h2>Explanation:</h2><h2></h2>

The code above has been written in Python. The following explains each line of the code.

<em>Line 1:</em> for x in range(7):

The built-in function <em>range(7)</em> generates integers between 0 and 7. 0 is included but not 7. i.e 0 - 6.

The for loop then iterates over the sequence of number being generated by the range() function. At each iteration, the value of x equals the number at that iteration. i.e

For the first iteration, x = 0

For the second iteration, x = 1

For the third iteration, x = 2 and so on up to x = 6 (since the last number, 7, is not included).

<em>Line 2:</em> if (x == 3 or x == 6):

This line checks for the value of x at each iteration. if the value of x is 3 or 6, then the next line, line 3 is executed.

<em>Line 3:</em> continue

The <em>continue</em> keyword is used to skip an iteration in a loop. In other words, when the continue statement is encountered in a loop, the loop skips to the next iteration without executing expressions that follow the <em>continue</em> statement in that iteration. In this case, the <em>print(x, end=' ') </em>in line 4 will not be executed when x is 3 or 6. That means 3 and 6 will not be printed.

<em>Line 4:</em> print(x, end=' ')

This line prints the value of x at each iteration(loop) and then followed by a single space. i.e 0 1 2 ... will be printed. Bear in mind that 3 and 6 will not be printed though.

<em>Line 5:</em> print("\n")

This line will be printed after the loop has finished execution. This line prints a new line character.

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Check the explanation

Explanation:

Code to copy:

// ConsoleApplication7.cpp : Defines the entry point for the console application.

#include "stdafx.h"

#include <iostream>

#include <cstring>

#include <string>

using namespace std;

int * letterFrequency(char s[]);

int main()

{

int *freq_letters;

char *s = new char[100];

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