def power_of_2(p):
if p == 2:
return True
elif p < 2:
return False
return power_of_2(p/2)
print(power_of_2(32))
The function keeps dividing the number by 2 until it is equal to 2 or the number ends up being less than 2. If at some point the number is equal to 2, it is a power of 2 otherwise it's not a power of 2.
Answer:
The complete method is as follows:
public static int divBySum(int[] arr, int num){
int sum = 0;
for(int i:arr){
if(i%num == 0)
sum+=i;
}
return sum;
}
Explanation:
As instructed, the program assumes that arr has been declared and initialized. So, this solution only completes the divBySum method (the main method is not included)
This line defines the method
public static int divBySum(int[] arr, int num){
This line declares and initializes sum to 0
int sum = 0;
This uses for each to iterate through the array elements
for(int i:arr){
This checks if an array element is divisible by num (the second parameter)
if(i%num == 0)
If yes, sum is updated
sum+=i;
}
This returns the calculated sum
return sum;
}
The IP connection-less protocol relies on TCP to guarantee delivery of data.
TCP- is transmission control protocal.TCP/IP allows one computer to talk to another via via the internet through compiling packets of data and sending them to right location.
They WHO did declare global health emergency at the end of January
Answer:
A
Explanation:
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