Let us make a list of all the details we have
We are given
The cost of each solid chocolate truffle = s
The cost of each cream centre chocolate truffle = c
The cos to each chocolate truffle with nuts = n
The first type of sweet box that contains 5 each of the three types of chocolate truffle costs $41.25
That is 5s+5c+5n = 41.25 (cost of each type of truffle multiplied by their respective costs and all added together)
The second type of sweet box that contains 10 solid chocolate trufles, 5 cream centre truffles and 10 chocolate truffles with nuts cost $68.75
That is 10s+5c+10n = $68.75
The third type of sweet box that contains 24 truffles evenly divided that is 12 each of solid chocolate truffle and chocolate truffle with nuts cost $66.00
That is 12s+12n=$66.00
Hence option C is the right set of equations that will help us solve the values of each chocolate truffle.
The area of the given composite figure is 34 square feet
<h3>Area of rectangle</h3>
Area of the rectangle = length * width
<h3>Get the area of the given composite figure</h3>
For the composite figure shown:
Area = (8*3) + (2 * 5)
Area = 24 + 10
Area = 34 square feet
Hence the area of the given composite figure is 34 square feet
Learn more on area of rectangle here: brainly.com/question/25292087
Answer:
Step-by-step explanation:
Part 15) we know that
Solve for k
That means ----> isolate the variable k
we have
substitute
Answer:
7.9 m
Step-by-step explanation:
Use the Pythagorean theorem: a²+b²=c²
This formula can be used to solve a side of any right (90°) triangle.
c² is the length of the hypotenuse (the diagonal side of the triangle, opposite to the 90° angle)
So, c = 32m.
Sides a and b are the legs of the triangle, but we only know one side. Plug numbers into the formula:
31² + b² = 32²
961 + b² = 1024 Subtract 961 from both sides to get b² by itself.
b² = 63
√b² = √63 Square root both sides to get b by itself.
b = 7.93725
Answer is 7.9 meters, rounded to tenths place
Answer:
a) rCn = 1176
b) 2352
Step-by-step explanation:
a)Each committee should be formed with 3 members ( no two members could be of the same state) then
Let´s fix a senator for any of the 50 states so in the new condition we need to combined 49 senators in groups of 2 then
rCn = n! / (n - r )! *r!
rCn = 49!/ (49 - 2)!*2!
rCn = 49*48*47! / 47!*2!
rCn = 49*48 /2
rCn = 1176
So we can choose in 1176 different ways a senator for a given state
b) To answer this question we have to note, that, 1176 is the number of ways a committee can be formed with senators of different sate (taking just one senator for state ) if we have 2 senators we need to multiply that figure by 2.
1176*2 = 2352
