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storchak [24]
3 years ago
11

Find the LCM of x2 + x,x2-1,x2-x

Mathematics
1 answer:
Katen [24]3 years ago
3 0

Answer: x(x+1)(x-1)

Step-by-step explanation:

x²+x=x(x+1)

x²-1=(x+1)(x-1)

x²-x=x(x-1)

ans:x(x+1)(x-1)

Step-by-step explanation:

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Let T: Mmxn(R)Mmxn(R) be the function defined
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True. See the explanation and proof below.

Step-by-step explanation:

For this case we need to remeber the definition of linear transformation.

Let A and B be vector spaces with same scalars. A map defined as T: A >B is called a linear transformation from A to B if satisfy these two conditions:

1) T(x+y) = T(x) + T(y)

2) T(cv) = cT(v)

For all vectors x,y \in V and for all scalars c \in R. And A is called the domain and B the codomain of T.

Proof

For this case the tranformation proposed is t: M_{mxn} (R) > M_{nxm} (R)

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1) The transpose of an nxm matrix is an nxm matrix

And the following conditions:

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And we can express like this T(A+B) =T(A) + T(B)

3) If A \in M_{mxn}(R) and c \in R then we have this:

T(cA) = (cA)^T = cA^T = cT(A)

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5 0
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