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patriot [66]
3 years ago
11

Midpoint of (1,3) and (4,-5)

Mathematics
1 answer:
crimeas [40]3 years ago
5 0

Answer:

The rigth answer is, ( 5/2 , -1 )

Step-by-step explanation:

To find the midpoint we use the respective formula:

m = ( x1 + x2 / 2 ,  y1 + y2 / 2 )

We replace:

m = ( 1 + 4/2  ,  3 + (- 5) / 2 )

We solve:

m = ( 5/2 ,  -1 )

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What is the approximate value of the square root of 8 rounded to the nearest tenth?
Elanso [62]

Answer:

Step-by-step explanation:

The square root of 8 to the nearest 100th is 2.83

The 3 is less than 5 so it does not alter the 8 at all.

The answer is 2.8

4 0
3 years ago
The number 27 is a perfect cube. 3 times 3 times 3 equals 27. find four other numbers that are perfect cubes and two numbers tha
yKpoI14uk [10]

Answer:

Numbers that aren't: 35 and 43. It can literally be any number.

Perfect cubes: 8,64,125,216. You can find perfect cubes by cubing any number. For example 6^3 (6 to the power of 3) is 216. A perfect cube.

6 0
3 years ago
Read 2 more answers
Help need answer please
antiseptic1488 [7]

Answer:

59.5

Step-by-step explanation:

1st tree to shadow ratio: 17:10

Plug the numbers in to get x:35

17:10=x:35

17/10=x/35

Multiply both sides by 35

595/10=x

59.5=x

5 0
3 years ago
I think I know this much so far for A (but I could be wrong):
Eduardwww [97]
Part A. You have the correct first and second derivative.

---------------------------------------------------------------------

Part B. You'll need to be more specific. What I would do is show how the quantity (-2x+1)^4 is always nonnegative. This is because x^4 = (x^2)^2 is always nonnegative. So (-2x+1)^4 >= 0. The coefficient -10a is either positive or negative depending on the value of 'a'. If a > 0, then -10a is negative. Making h ' (x) negative. So in this case, h(x) is monotonically decreasing always. On the flip side, if a < 0, then h ' (x) is monotonically increasing as h ' (x) is positive.

-------------------------------------------------------------

Part C. What this is saying is basically "if we change 'a' and/or 'b', then the extrema will NOT change". So is that the case? Let's find out

To find the relative extrema, aka local extrema, we plug in h ' (x) = 0
h  ' (x) = -10a(-2x+1)^4
0 = -10a(-2x+1)^4
so either
-10a = 0 or (-2x+1)^4 = 0
The first part is all we care about. Solving for 'a' gets us a = 0. 
But there's a problem. It's clearly stated that 'a' is nonzero. So in any other case, the value of 'a' doesn't lead to altering the path in terms of finding the extrema. We'll focus on solving (-2x+1)^4 = 0 for x. Also, the parameter b is nowhere to be found in h ' (x) so that's out as well. 
6 0
3 years ago
I NEED SOMEONE TO HELP ASAP: I just need someone to classify all of these things
Sergio039 [100]
Integer, natural, whole, rational, irrational, natural (15/3=5), integer (-12/6=-2), rational, irrational, rational, rational

Natural-the counting numbers (1,2,3,100...)
Whole-all natural AND 0
Integers-add negative numbers (no fractions)
Rational-add fractions and decimals
Irrational-numbers that can’t be a fraction (square root of 3, pi)
Real-all numbers
7 0
3 years ago
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