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3 years ago

If each triangle is the right Triangle yes or no?

Mathematics

1 answer:

SIZIF [17.4K]3 years ago

7 0

Answer:

This is not a right triangle

Step-by-step explanation:

right triangle has a 90° angle and this triangle does not have a 90° angle

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Please I really need help with this

romanna [79]

Answer:

A, 14

Step-by-step explanation:

Assuming that she has a total of d dollars, and spends half of it, then we have 1/2d. She then spends <em>another</em> 6 dollars, and therefore we would subtract. She is left with one dollar.

1/2d-6=1

Working backwards, we can solve for d, her total amount of money:

1/2d=7

d=14

<em>I hope this helps! :)</em>

6 0

3 years ago

Pls help me I’ll give brainliest pls dont answer if you don’t know

Delvig [45]

Answer:

Species

Step-by-step explanation:

i read the passage hence is how i got my answers

3 0

3 years ago

Read 2 more answers

Which number line shows the solution to the inequality n > 4?

lesya692 [45]

Answer:

It would be A

Step-by-step explanation:

4 0

3 years ago

Answer the ones you know

vladimir2022 [97]

For question 2 it is 15

Because: 4 time 6 is 24 and then you minus 9 which is 15

So there you have it the answer is 15

8 0

3 years ago

Read 2 more answers

How do you solve these equations? I don't want you to answer all of them, just tell me how to solve each type of equation on the

miss Akunina [59]

Answer:

8. Identify the common denominator; express each fraction using that denominator; combine the numerators of those rewritten fractions and express the result over the common denominator. Factor out any common factors from numerator and denominator in your result. (It's exactly the same set of instructions that apply for completely numerical fractions.)

9. As with numerical fractions, multiply the numerator by the inverse of the denominator; cancel common factors from numerator and denominator.

10. The method often recommended is to multiply the equation by a common denominator to eliminate the fractions. Then solve in the usual way. Check all answers. If one of the answers makes your multiplier (common denominator) be zero, it is extraneous. (10a cannot have extraneous solutions; 10b might)

Step-by-step explanation:

For a couple of these, it is helpful to remember that (a-b) = -(b-a).

$\dfrac{5}{x+2}+\dfrac{25-x}{x^2-3x-10}=\dfrac{5(x-5)}{(x+2)(x-5)}+\dfrac{25-x}{(x+2)(x-5)}\\\\=\dfrac{5x-25+25-x}{(x+2)(x-5)}=\dfrac{4x}{x^2-3x-10}$

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$\displaystyle\frac{\left(\frac{x}{x-2}\right)}{\left(\frac{2x}{2-x}\right)}=\frac{x}{x-2}\cdot\frac{-(x-2)}{2x}=\frac{-x(x-2)}{2x(x-2)}=-\frac{1}{2}$

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$\dfrac{3}{x-1}+\dfrac{6}{x^2-3x+2}=2\\\\\dfrac{3(x-2)}{(x-1)(x-2)}+\dfrac{6}{(x-1)(x-2)}=\dfrac{2(x-1)(x-2)}{(x-1)(x-2)}\\\\3x-6+6=2(x^2-3x+2) \qquad\text{multiply by the denominator}\\\\2x^2-9x+4=0 \qquad\text{subtract 3x}\\\\(2x-1)(x-4)=0 \qquad\text{factor; x=1/2, x=4}$

Neither solution makes any denominator be zero, so both are good solutions.

8 0

3 years ago