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lianna [129]
3 years ago
10

A triangle has angle <1 and <2 as a remote interior angles with respect to exterior angle <3. Given that m<1 =50 and

m<2=70, Alicia reasoned that m<3 must be 60. Explain Alicias error
Mathematics
1 answer:
Step2247 [10]3 years ago
7 0
∠1 = 50°
∠2=70°
If ∠3 is exterior ansgle with respect to ∠1 and ∠2, ∠3 must be ∠1+∠2 = 50°+70° =120°..Whereas, the interior angle with ∠3 will be 180°-120°=60°
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When testing for current in a cable with eight ​color-coded wires, the author used a meter to test five wires at a time. How man
balu736 [363]

Answer:

56 different tests

Step-by-step explanation:

Given:

Number of wires available (n) = 8

Number of wires taken at a time for testing (r) = 5

In order to find the number of different tests required for every possible pairing of five wires, we need to find the combination rather than their permutation as order of wires doesn't disturb the testing.

So, finding the combination of 5 pairs of wires from a total of 8 wires is given as:

^nC_r=\frac{n!}{r!(n-r)!}

Plug in the given values and solve. This gives,

^8C_5=\frac{8!}{5!(8-5)!}\\\\^8C_5=\frac{8\times 7\times 6\times 5!}{5!\times 3\times2\times1}\\\\^8C_5=56

Therefore, 56 different tests are required for every possible pairing of five ​wires.

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3 years ago
List the next four multiples of each fraction 1/4
julsineya [31]

Answer:

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Step-by-step explanation:

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3 years ago
If joan reads 96 pages in 4 hours how long will it take her to read 240
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Answer:

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7 0
3 years ago
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Need help with this problem
Romashka-Z-Leto [24]

3x = 4x + 2

-4x  -4x

-1x = 2

----  -----

-1      -1

x = -2

Check:

3(-2) = 4(-2) + 2

-6 = -8 + 2

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4 0
3 years ago
Al factorizar el trinomio cuadrado perfecto, obtenemos el siguiente resultado: (que no se como resolver) xd algun pro que sepa r
PolarNik [594]

Answer:

\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8=\left(\frac{10}{9}m^4p^{6}q^{8}z-\frac{1}{7}mpz^4\right)^2

Step-by-step explanation:

<u>Trinomio Cuadrado Perfecto</u>

El producto notable llamado cuadrado de un binomio se expresa como:

(a-b)^2=a^2-2ab+b^2

Si se tiene un trinomio, es posible convertirlo en un cuadrado perfecto si cumple con las condiciones impuestas en la fórmula:

* El primer término es un cuadrado perfecto

* El último término es un cuadrado perfecto

* El segundo término es el doble del proudcto de los dos términos del binomio.

Tenemos la expresión:

\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8

Calculamos el valor de a como la raiz cuadrada del primer término del trinomio:

\displaystyle a=\sqrt{\frac{100}{81}m^8p^{12}q^{16}z^2}

\displaystyle a=\frac{10}{9}m^4p^{6}q^{8}z

Calculamos el valor de a como la raiz cuadrada del primer término del trinomio:

\displaystyle b=\sqrt{\frac{1}{49}m^2p^2z^8

\displaystyle b=\frac{1}{7}mpz^4

Nos cercioramos de que el término central es 2ab:

\displaystyle 2ab=2\frac{10}{9}m^4p^{6}q^{8}z\frac{1}{7}mpz^4

Operando:

\displaystyle 2ab=\frac{20}{63}m^5p^7q^8z^5

Una vez verificado, ahora podemos decir que:

\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8=\left(\frac{10}{9}m^4p^{6}q^{8}z-\frac{1}{7}mpz^4\right)^2

5 0
2 years ago
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