Answer:
8/9
Step-by-step explanation:
3/6 + 7/ 18
Make the denominator common by finding the LCM = 18
Multiply 3 by 3
Therefore sum = 3*3 + 7/ 18
sum = 9+7/18
sum = 16/18
=> 8/9
Please mark my answer as the brainliest for further answers :)
35+57 is the answer for you question
Extranious solution is mostly when you take the square root of negative number
what you want to do is math stuff
translate
remember that
![x^ \frac{1}{2} = \sqrt{x}](https://tex.z-dn.net/?f=x%5E%20%5Cfrac%7B1%7D%7B2%7D%20%3D%20%5Csqrt%7Bx%7D%20)
so
![x^ \frac{3}{2}=x \sqrt{x}](https://tex.z-dn.net/?f=x%5E%20%5Cfrac%7B3%7D%7B2%7D%3Dx%20%5Csqrt%7Bx%7D%20%20)
7.
![(x+1) \sqrt{x+1} -2=25](https://tex.z-dn.net/?f=%28x%2B1%29%20%5Csqrt%7Bx%2B1%7D%20-2%3D25)
add 2 to both sides
![(x+1) \sqrt{x+1}=27](https://tex.z-dn.net/?f=%28x%2B1%29%20%5Csqrt%7Bx%2B1%7D%3D27)
square both sides
![(x+1)^3=729](https://tex.z-dn.net/?f=%28x%2B1%29%5E3%3D729)
cube root both sides
x+1=9
minus 1
x=8
8.
square both sides
![3x+7=x^2-2x+1](https://tex.z-dn.net/?f=3x%2B7%3Dx%5E2-2x%2B1)
using math
0=x²-5x-6
x=6 or -1
if we do x=-1, we get
√4=-2, which is kind of true, but we normally find the principal root (posiitive0
-1 is extraious
x=6
9.
add √(x-1) to both sides then square both sides
![2x+6=4 \sqrt{x+1}+x+5](https://tex.z-dn.net/?f=2x%2B6%3D4%20%5Csqrt%7Bx%2B1%7D%2Bx%2B5)
minus (x+5) from both sides
![x+1=4 \sqrt{x+1}](https://tex.z-dn.net/?f=x%2B1%3D4%20%5Csqrt%7Bx%2B1%7D%20)
square both sides
![x^2+2x+1=16x+16](https://tex.z-dn.net/?f=x%5E2%2B2x%2B1%3D16x%2B16)
using math
x=-1 or 15
if we had x=-1, we would be having √(-1-1) which is sqrt of negative which is not allowed
x=15
The answer is 167/3 due to finding the LCD and then combining