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2 years ago

Can someone plz explain how to do this

Mathematics

1 answer:

swat322 years ago

5 0

Answer:

-2

Step-by-step explanation:

First, you need to find the equation.

f(x) = -3x + b

Now we need to find the y-intercept.

f(x) = -3x + b

f(-9) = -3(1) + b

-9 = -3 + b

-6 = b

f(x) = -3x - 6

The zero of f means that f(x) = 0

f(0) = -3x - 6

f(6) = -3x

x = -2

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The average value of a function f over the interval [−2,3] is −6 , and the average value of f over the interval [3,5] is 20. Wha

Xelga [282]

Answer:

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

Step-by-step explanation:

Let suppose that function $f$ is continuous and integrable in the given intervals, by integral definition of average we have that:

$\frac{1}{3-(-2)} \int\limits^{3}_{-2} {f(x)} \, dx = -6$ (1)

$\frac{1}{5-3} \int\limits^{5}_{3} {f(x)} \, dx = 20$ (2)

By Fundamental Theorems of Calculus we expand both expressions:

$\frac{F(3)-F(-2)}{3-(-2)} = -6$

$F(3) - F(-2) = -30$ (1b)

$\frac{F(5)-F(3)}{5-3} = 20$

$F(5) - F(3) = 40$ (2b)

We obtain the average value of $f$ over the interval $[-2, 5]$ by algebraic handling:

$F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)$

$F(5) - F(-2) = 10$

$\frac{F(5)-F(-2)}{5-(-2)} = \frac{10}{5-(-2)}$

$\bar f = \frac{10}{7}$

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

4 0

2 years ago

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Nadya [2.5K]

Answer:

eweweweweweewwe

Step-by-step explanation:

4 0

2 years ago

19. Given that angle BFC = 58°. Angle BXG = 48° and angle CBF 22 Find () 2BGX (iv) BCG (i) 2BGF (iv) ZBFG (ii) BCF H EE 58 48° D

RoseWind [281]

The unknown angles in the cyclic quadrilateral is as follows:

∠BGX = 74° (sum of angles in a triangle)

∠BGF = 180° (opposite angles of cyclic quadrilateral are supplementary)

∠BCF = 100°(sum of angles in a triangle)

∠BCG = 26°

∠BFG = 22°

<h3>Cyclic Quadrilateral</h3>

A cyclic quadrilateral has all its angles equal to 360 degrees. The sum of angles in a cyclic quadrilateral is equals to 360 degrees.

Let's find the missing angles as follows:

∠BGX = 180 - 48 - 58 = 74° (sum of angles in a triangle)

∠BGF = 180 - 100 = 80° (opposite angles of cyclic quadrilateral are supplementary)

∠BCF = 180 - 22 - 58 = 100°(sum of angles in a triangle)

∠BCG = 100 - 74 = 26°

∠BFG ≅ CBF = 22°(alternate angles)

learn more on angles here: brainly.com/question/19430381

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1 year ago

What is 19% as a decimal and a fraction?

kondaur [170]

Answer:

Decimal - 0.19 Fraction - 19/100

Step-by-step explanation:

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2 years ago

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Can someone help me ? i have no clue how to figure this out

Ad libitum [116K]

$\cos t (\sec t - \cos t) = \sin^2 t$

$\cos t (\dfrac{1}{\cos t} - \cos t) = \sin^2 t$

$\dfrac{\cos t}{\cos t} - \cos^2 t = \sin^2 t$

$1 - \cos^2 t = \sin^2 t$

Use the identity: $\sin^2 t + \cos^2 t = 1$ and solve for $\sin^2 t$ . You get: $\sin^2 t = 1 - \cos^2 t$

Do the substitution on the left side to get:

$\sin^2 t = \sin ^2 t$

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2 years ago

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