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castortr0y [4]
4 years ago
14

I NEED HELP ON THESE QUESTIONS PLZZZZZ (Specifically question 2)

Mathematics
1 answer:
Hitman42 [59]4 years ago
3 0
2 is 21.67 percent
(21.6666666666666666666666 or repeating)
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PLEASE HELP FIGURE OUT THE EQUATION!!!
lisabon 2012 [21]

f = twenty bill

f = fifty bill

f + t = 18(gave total 18 bills) and 50f + 20t = 450 ($450 cash a check)

Answer is B.

f + t = 18 ; 50f + 20t = 450

3 0
4 years ago
Two congruent triangles are given.
bezimeni [28]
I think the correct answer would be the 3rd one
4 0
3 years ago
Part 2: NO LINKS!! NOT MULTIPLE CHOICE! Please help me​
Dmitry_Shevchenko [17]

Answer:

(see attachment for tree diagram)

\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}

<h3><u>Part (a)</u></h3>

\textsf{P(Head) and P(3)}=\sf \dfrac{1}{2} \times \dfrac{1}{6}=\dfrac{1}{12}

<h3><u>Part (b)</u></h3>

\textsf{P(Tail) and P(even)}=\sf \dfrac{1}{2} \times \dfrac{3}{6}=\dfrac{3}{12}=\dfrac{1}{4}

<h3><u>Part (c)</u></h3>

\textsf{P(not 6)}=\sf 1-\textsf{P(6)}=1-\dfrac{1}{6}=\dfrac{5}{6}

\implies \textsf{P(Head) and P(not 6)}=\sf \dfrac{1}{2} \times \dfrac{5}{6}=\dfrac{5}{12}

<h3><u>Part (d)</u></h3>

As the six-sided die does not have a side labelled "7", the probability of rolling a 7 is zero.

\implies \textsf{P(Head) and P(7)}=\sf \dfrac{1}{2} \times 0=0

7 0
2 years ago
a small book publisher knows that 13 books weigh 15 lbs how much do 45 books weigh? (round to the nearest integer)
Alona [7]

Answer:

39

Step-by-step explanation:

15 divied by 13=  .86

.86 times 45 = 38.7 they you round

5 0
3 years ago
Read 2 more answers
QUICK QUESTION: did I do this right?
zloy xaker [14]
It it fully correct
Hope you have a good day!
Can ai get brainliest?
8 0
3 years ago
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