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2 years ago

Heart 1 is translated 3 units down to heart 2. Which shows this transformation?

Mathematics

2 answers:

Marina CMI [18]2 years ago

7 0

Answer:

It is the 4th image

Step-by-step explanation:

I took the test

oksian1 [2.3K]2 years ago

3 0

Answer:

Image IV

Step-by-step explanation:

We are given that

Heart 1 is translated 3 units down to heart 2.

We have to find the image which shows this transformation.

The translation rule when a figure is shift 3 units down is given by

$(x,y)\rightarrow (x,y-3)$

The coordinates of a point lie on heart are (-2.5,3)

After translation 3 units, the coordinates of corresponding point which lie on the heart

$(-2.5,3)\rightarrow (-2.5,0)$

Therefore,the heart shift from II quadrant to III quadrant.

Image I is not true because the heart 1 shift to heart 2 in quadrant III not in IV quadrant.

In image II ,the corresponding point of the point (-2.5,3) is (-2.5,-3).

Image II is not true because the corresponding point is (-2.5 ,0) not (-2.5,-3).

Image III is not true because heart 2 should be in quadrant III not in quadrant I after translation 3 units down of heart 1.

Image IV is true because the corresponding point of the point (-2,5,3) is (-2.5,0) and heart 2 lies in quadrant III.

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Olegator [25]

The length of train is 120 meters

The speed of train is 25 meter per second

Solution:

The speed is given by formula:

$speed = \frac{distance}{time}$

Given that,

It takes a train 60 seconds to completely drive through a bridge of 1260 m

And 90 seconds to completely drive through a tunnel of 2010 m

Let the length of the train be "x"

The total distance travelled by the train across the bridge is given by:

total distance = x + 1260 + x = 2x + 1260

[ here we use x + x to represent that train completely drives through bridge ]

The time taken is given as 60 seconds

Therefore, the speed is given as:

$speed = \frac{2x+ 1260}{60}$

The total distance travelled by the train through the tunnel is given by:

total distance = x + 2010 + x = 2x + 2010

The time taken is given as 90 seconds

Therefore, the speed is given as:

$speed = \frac{2x+ 2010}{90}$

The speed of the train was the same in both cases.

Equate both speeds

$\frac{2x+ 1260}{60} = \frac{2x+ 2010}{90}$

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Thus length of train is 120 meters

Find the speed of train:

$speed = \frac{2x+ 1260}{60}\\\\speed = \frac{2(120) + 1260)}{60}\\\\speed = 25$

Thus speed of train is 25 meter per second

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