Answer:
The p-value of the test is 0.0007 < 0.05, indicating that the the snowfall for the 1993-1994 winters was higher than the previous 20-year average.
Step-by-step explanation:
20-year mean snowfall in the Denver/Boulder region is 28.76 inches. Test if the snowfall for the 1993-1994 winters has higher than the previous 20-year average.
At the null hypothesis, we test if the average was the same, that is, of 28.76 inches. So
![H_0: \mu = 28.76](https://tex.z-dn.net/?f=H_0%3A%20%5Cmu%20%3D%2028.76)
At the alternate hypothesis, we test if the average incresaed, that is, it was higher than 28.76 inches. So
![H_1: \mu > 28.76](https://tex.z-dn.net/?f=H_1%3A%20%5Cmu%20%3E%2028.76)
The test statistic is:
![z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}](https://tex.z-dn.net/?f=z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%7D)
In which X is the sample mean,
is the value tested at the null hypothesis,
is the standard deviation and n is the size of the sample.
28.76 is tested at the null hypothesis:
This means that ![\mu = 28.76](https://tex.z-dn.net/?f=%5Cmu%20%3D%2028.76)
Standard deviation of 7.5 inches. However, for the winter of 1993-1994, the average snowfall for a sample of 32 different locations was 33 inches.
This means that
.
Value of the test statistic:
![z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}](https://tex.z-dn.net/?f=z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%7D)
![z = \frac{33 - 28.76}{\frac{7.5}{\sqrt{32}}}](https://tex.z-dn.net/?f=z%20%3D%20%5Cfrac%7B33%20-%2028.76%7D%7B%5Cfrac%7B7.5%7D%7B%5Csqrt%7B32%7D%7D%7D)
![z = 3.2](https://tex.z-dn.net/?f=z%20%3D%203.2)
P-value of the test and decision:
The p-value of the test is the probability of finding a sample mean above 33, which is 1 subtracted by the p-value of z = 3.2. In this question, we consider the standard level
.
Looking at the z-table, z = 3.2 has a p-value of 0.9993.
1 - 0.9993 = 0.0007
The p-value of the test is 0.0007 < 0.05, indicating that the the snowfall for the 1993-1994 winters was higher than the previous 20-year average.