Ask question

Ask question

All categories

3 years ago

7

Two ships leave a harbor together, traveling on courses that have an angle of 135 degrees between them. if they travel 402 miles

, how far apart are they? question 11 options:
a.586.51 miles

b.742.80 miles

c.803.21 miles

d.551,750.57 miles

e.645,151.56 miles

2 answers:

Rom4ik [11]3 years ago

7 0

I did the problem in the attached image

Sauron [17]3 years ago

7 0

Answer:

b.Distance between two ships=742.80 miles

Step-by-step explanation:

We are given that two ships leave a harbor together ,travelling on course that have an angle of 135 degrees between them .

Distance travel by one ship=402 miles

Distance travel by second ship=402 miles

Angle between them =135 degrees

Distance between two ships = $\sqrt{(402)^2+(402)^2-2(402)^2 cos 135}$

Distance between two ships= $402\sqrt{1+1+2 cos (90+45)}$

Distance between two ships= $402\sqrt{2+2sin45}$

Distance between two ships= $402\sqrt{2+\sqrt2}$

Distance between two ships=742.799=742.80 miles

Distance between two ships=742.80 miles

Hence, option b is true.

You might be interested in

Water flows straight down from an open faucet. The cross-sectional area of the faucet is 1.00 × 10 − 4 m², and the speed of the

Setler79 [48]

Answer: $A_2=0.349\times 10^{-4} m^2$

Step-by-step explanation:

Given

velocity $v_1=0.72 m/s$

Area of cross-section $A_1=1\times 10^{-4} m^2$

velocity after Falling 0.19 m

$v_2^2-v_1^2=2g\cdot h$

$v_2^2=v_1^2+2g\cdot h$

$v_2^2=(0.72)^2+2\times 9.8\times 0.19$

$v_2^2=0.518+3.724$

$v_2=\sqrt{4.24}$

$v_2=2.05 m/s$

conserving Flow

$A_1v_1=A_2v_2$

$1\times 10^{-4}\times 0.72=A_2\times 2.05$

$A_2=0.349\times 10^{-4} m^2$

8 0

3 years ago

One of the most fiercely debated topics in sports is the hot hand theory. The hot hand theory says that success breeds success.

Korvikt [17]

Answer:

The answer to the question is

The theory of the hot hand is valid in my opinion.

Step-by-step explanation:

The phenomenon of a "hot hand" is that a person who achieves a successful outcome at an attempt has a higher probability of coming out successful in subsequent attempts at the same event.

Based on evidence from the sampled statistics, the likelihood of achieving an increased probability of success on subsequent attempt on the condition that previous attempts were successful in my opinion is plausible. This is because the ability to score points at a game is dependent on several variables, all of which are from previous occurrence, such dependent variables include

1. The inherent ability of the sport athlete to deliver the required input for success. This is a conditional probability for success as such this forms part of the increased acceptance level for the "hot hand" phenomenon

2. Conditions of play may favor a particular probability than others resulting in a change in the mean, and the standard deviation of the distribution resulting in a skewed outcome

3. Increased opportunity giving to the athlete that previously had a successful attempt possibly by the athlete himself by way of confidence, the audience by way of focus on the outcome of the athletes attempt, and the administrators by way of trying to make it achievable and hence easier within the rules for the athlete have a successful attempt

The "hot hand" (also known as the "hot hand phenomenon" or "hot hand fallacy") is the purported phenomenon that a person who experiences a successful outcome has a greater chance of success in further attempts. The concept is often applied to sports and skill-based tasks in general and originates from basketball, whereas a shooter is allegedly more likely to score if their previous attempts were successful, i.e. while having "hot hands.” While previous success at a task can indeed change the psychological attitude and subsequent success rate of a player, researchers for many years did not find evidence for a "hot hand" in practice, dismissing it as fallacious. However, later research questioned whether the belief is indeed a fallacy.[1][2] Recent studies using modern statistical analysis show there is evidence for the "hot hand" in some sporting activities.[2]

7 0

2 years ago

Vanya collects vintage albums. Each storage unit holds 16 albums. She gave 3 albums to her cousin as a graduation present. Which

enot [183]

Answer:

Step-by-step explanation: do y’all know answer

7 0

2 years ago

Read 2 more answers

Passing through (-2,1 ) and perpendicular to<br> 4x + 7y + 3 = 0.

Lunna [17]

Answer:

<h2>7x - 4y + 18 = 0</h2>

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$y=mx+b$

m - slope

b - y-intercept

========================================

Let

$k:y=m_1x+b_1\\\\l:y=m_2x+b_2\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\l\ \parallel\ k\iff m_1=m_2$

========================================

We have the equation of a line in a general form (Ax + By + C = 0)

Convert it to the slope-intercept form:

$4x+7y+3=0$ <em>subtract 7y from both sides</em>

$4x+3=-7y$ <em>divide both sides by (-7)</em>

$-\dfrac{4}{7}x-\dfrac{3}{7}=y\to m_1=-\dfrac{4}{7}$

Therefore

$m_2=-\dfrac{1}{-\frac{4}{7}}=\dfrac{7}{4}$

We have the equation:

$y=\dfrac{7}{4}x+b$

Put the coordinates of the point (-2, 1) to the equation, and solve for <em>b</em> :

$1=\dfrac{7}{4}(-2)+b$

$1=-\dfrac{7}{2}+b$ <em>multiply both sides by 2</em>

$2=-7+2b$ <em>add 7 to both sides</em>

$9=2b$ <em>divide both sides by 2</em>

[te]x\dfrac{9}{2}=b\to b=\dfrac{9}{2}[/tex]

Finally:

$y=\dfrac{7}{4}x+\dfrac{9}{2}$ - <em>slope-intercept form</em>

Convert to the general form:

$y=\dfrac{7}{4}x+\dfrac{9}{2}$ <em>multiply both sides by 4</em>

$4y=7x+18$ <em>subtract 4y from both sides</em>

$0=7x-4y+18$

6 0

2 years ago

Find the average rate of change of the function defined by the following table. x y -2 -5 2 35 6 75 10 115

Pani-rosa [81]

By definition we have that the average rate of change of the function is:

$AVR = \frac{f(x2) - f(x1)}{x2 - x1}$

Evaluating the function for the complete interval we have that the AVR is given by:

$AVR = \frac{115 - (-5)}{10 - (-2)}$

Rewriting we have:

$AVR = \frac{115+5}{10+2}$

Simplifying the expression we have:

$AVR = \frac{120}{12}$

$AVR = 10$

Answer:

the average rate of change of the function defined by the table is:

$AVR = 10$

6 0

2 years ago