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rosijanka [135]
3 years ago
15

2. (05.03 MC)

Mathematics
2 answers:
tangare [24]3 years ago
8 0

Answer:

Step-by-step explanation:

Part A:

We have two lines: y = 2 - x and y = 4x + 3 . Given two equations that are both required to be true. The answer is the points where the lines cross, this means we have to make the equations equal to each other. It will look like this:

                                             2 - x = 4x + 3

Part B:

In order to solve the equation we need to put the like terms together. So we will add x on each side.

                                              2 - x = 4x + 3

                                                   +x   +x

So now we get:

                                                  2 = 5x + 3

Now that x is on one side and is positive we will move 3 on the left side by subtracting it from each side.

                                                  2 = 5x + 3

                                                   -3         -3

So now we get:

                                                       -1 = 5x

Now that the like terms have been combined we need to find out what x alone is so we divide 5 on each side:

                                                           \frac{-1}{5} = \frac{5x}{5}

Now we see that:

                                                         x = -\frac{1}{5}

DedPeter [7]3 years ago
6 0
We have that
<span>y = 2−x
and
y = 4x + 3 

we know that

Part a) 
</span>the graph of both lines, if it is a system of consistent equations, is going to intersect in a single point that will belong to both lines, so the values ​​of that point will satisfy both equations

part b) see the attached table  
<span>observing the table it is deduced that the solution value of x must be in the interval [-1, 0]
</span>
part c)
using a graph tool
see the attached figure

<span>the system is solved graphically, by identifying the point of intersection of both lines
</span>
the solution is the point (-0.2, 2.2)

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Answer:

a) r=\frac{9(396)-(18)(153)}{\sqrt{[9(51) -(18)^2][9(3141) -(153)^2]}}=1  

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And we can find the intercept using this:  

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Step-by-step explanation:

We have the following data:

Number of hours spent practicing (x) 0 0.5 1 1.5 2 2.5 3 3.5 4

Score in the game (y) 5 8 11 14 17 20 23 26 29

Part a

The correlation coefficient is given:

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}  

For our case we have this:

n=9 \sum x = 18, \sum y = 153, \sum xy = 396, \sum x^2 =51, \sum y^2 =3141  

r=\frac{9(396)-(18)(153)}{\sqrt{[9(51) -(18)^2][9(3141) -(153)^2]}}=1  

We have a perfect linear relationship between the two variables

Part b

m=\frac{S_{xy}}{S_{xx}}  

Where:  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}  

With these we can find the sums:  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=51-\frac{18^2}{9}=15  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i){n}}=396-\frac{18*153}{9}=90  

And the slope would be:  

m=\frac{90}{15}=6  

Nowe we can find the means for x and y like this:  

\bar x= \frac{\sum x_i}{n}=\frac{18}{9}=2  

\bar y= \frac{\sum y_i}{n}=\frac{153}{9}=17  

And we can find the intercept using this:  

b=\bar y -m \bar x=17-(6*2)=5  

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y=6 x +5  

Part c

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