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3 years ago

How many yards is 38.7 cm? Write your answer in scientific notation with 3 sig figs.

Mathematics

1 answer:

Kaylis [27]3 years ago

8 0

Answer:

=0.423 yards (3 sig figs.)

Step-by-step explanation:

38.7÷91.44

=0.4232283

=0.423 yards (3 sig figs.)

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A bus can hold 44 people, if there are 35 students in samantha's class, how many more people can ride on the bus?, answer needs

OLEGan [10]

To find out how many people can ride on the bus, all you have to do is subtract 35 from 44, the answer being 9.

My attempt at a number line on Brainly:
<-------------------------------------->
' ' ' ' ' ' ' ' '
35 44

Really, you should probably just do this part yourself.

8 0

4 years ago

What is the equation of the following line written in slope-intercept form -2/3 and -1/-4? y = -11x - 7 y = -7x + 11 y = -7x - 1

Snowcat [4.5K]

Answer:

$y=-7x-11$

Step-by-step explanation:

Given:

The two points on the line are $(-2,3)$ and $(-1,-4)$ .

The slope of the line joining two points $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is given as:

$Slope,m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Here, $x_{1}=-2,y_{1}=3,x_{2}=-1,y_{2}=-4$

∴ $m=\frac{-3-4}{-1-(-2)}=\frac{-7}{-1+2}=\frac{-7}{1}=-7$

Equation of line with a point $(x_{1},y_{1})$ and slope $m$ is given as:

$y-y_{1}=m(x-x_{1})$

Plug in -2 for $x_{1}$ , 3 for $y_{1}$ and -7 for $m$ . This gives,

$y-3=-7(x-(-2))\\y-3=-7(x+2)\\y-3=-7x-(7\times 2)\\y-3=-7x-14\\y=-7x-14+3\\y=-7x-11$

Therefore, the equation of the line in vertex form is $y=-7x-11$ .

4 0

3 years ago

If a hospital patient is given 50 milligrams of medicine which leaves the bloodstream at 10% per hour, how many milligrams of me

12345 [234]

A(t) = 50 e^-(0.1 x 6) = 50 e^-0.6 = 50 x 0.5488 = 27.44 mg

3 0

3 years ago

Read 2 more answers

The length of the shadow of a pole on level ground increases by 90m when the angle of elevation of the sun changes from 58° to 3

viva [34]

Answer:

119.45 m

Step-by-step explanation:

Given:

When angle of elevation of the sun changes from 58° to 36° the length of shadow of a pole increases by 90 m.

To find:

Length of pole = ?

Solution:

Kindly refer to the attached image.

$\triangle ABC$ represents the 1st angle of elevation of sun i.e. 58°

$\triangle ABD$ represents the 2nd angle of elevation of sun i.e. 36°

Change in shadow is represented by CD = 90 m

Let height of pole, AB = $h$ m

Let side BC = $x$ m

Now, let us apply tangent rules in $\triangle ABC, \triangle ABD$ one by one:

$tan\theta = \dfrac{Perpendicular}{Base}\\\Rightarrow tan58^\circ=\dfrac{AB}{BC}\\\Rightarrow tan58^\circ=\dfrac{h}{x}\\\Rightarrow x = 0.624h ..... (1)$

$tan36^\circ = \dfrac{h}{x+90}$

Putting value of $x$ using equation (1):

$tan36^\circ = \dfrac{h}{0.624h+90}\\\Rightarrow 0.726\times 0.624h+0.726\times 90 = h\\\Rightarrow h-0.453h =65.34\\\Rightarrow \bold{h = 119.45\ m}$

119.45 m is the height of pole.

7 0

4 years ago

A system has a level 1 cache and a level 2 cache. The hit rate of the level 1 cache is 95%, and the subsequent hit rate of the l

ankoles [38]

Answer:

Step-by-step explanation:

H1 = Hit rate of level 1 cache = 0.95

T1 = Access time for level 1 cache = 1

H2 = Hit rate of level 2 cache = 0.8

T2 = Access time for level 2 cache = 3

Hm = Hit rate of Main Memory = 1

Tm = Access time for Main Memory = 80

Average access time = [H1*T1]+[(1-H1)*H2*T2]+[(1-H1)(1-H2)*Hm*Tm]

= [0.95*1]+[1-0.95]*0.8*3]+[(1-0.95)(1-0.8)*1*80]

= [0.95+0.05*0.8*3]+[0.05*0.2*1.80]

= 2.4+0.018 = 2.418

Average access time = 2.418

7 0

3 years ago