Answer:
0.999987
Step-by-step explanation:
Given that
The user is a legitimate one = E₁
The user is a fraudulent one = E₂
The same user originates calls from two metropolitan areas = A
Use Bay's Theorem to solve the problem
P(E₁) = 0.0131% = 0.000131
P(E₂) = 1 - P(E₁) = 0.999869
P(A/E₁) = 3% = 0.03
P(A/E₂) = 30% = 0.3
Given a randomly chosen user originates calls from two or more metropolitan, The probability that the user is fraudulent user is :
= 0.999986898 ≈ 0.999987
Answer:
Doman is the x intercpet range
Step-by-step explanation:
all real numbers is the domain since the function goes on and on forever and will at one point get to 1 billion or trillion or just on and on forever.
Answer:
One time
Step-by-step explanation:
In both the numbers 72 and 78, the place value of 7 is 70.
Hence, 7 in 72 represents one time the value of the 7 in 78.
Answer:
$9$
Step-by-step explanation:
Given: Thea enters a positive integer into her calculator, then squares it, then presses the $\textcolor{blue}{\bf\circledast}$ key, then squares the result, then presses the $\textcolor{blue}{\bf\circledast}$ key again such that the calculator displays final number as $243$.
To find: number that Thea originally entered
Solution:
The final number is $243$.
As previously the $\textcolor{blue}{\bf\circledast}$ key was pressed,
the number before $243$ must be $324$.
As previously the number was squared, so the number before $324$ must be $18$.
As previously the $\textcolor{blue}{\bf\circledast}$ key was pressed,
the number before $18$ must be $81$
As previously the number was squared, so the number before $81$ must be $9$.
Answer:
LM = 2.82 ft
MN = 2.39 ft
Step-by-step explanation:
We suppose ΔGNF is isosceles and GF bisect ∠NGF, so that GK ⊥ NF
LH // MJ // NK
GL / GH = LM / HJ = MN / JK
11.3 / 10.4 = LM / 2.6 = MN / 2.2
LM = 11.3 / 10.4 x 2.6 = 2.82
MN = 11.3 / 10.4 x 2.2 = 2.39
